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Python function to ask for a multiple-choice answer


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3












$begingroup$


# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in len(options):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer


I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?










share|improve this question









New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    "The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
    $endgroup$
    – Mast
    3 hours ago










  • $begingroup$
    Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
    $endgroup$
    – JDG
    1 hour ago


















3












$begingroup$


# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in len(options):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer


I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?










share|improve this question









New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    "The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
    $endgroup$
    – Mast
    3 hours ago










  • $begingroup$
    Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
    $endgroup$
    – JDG
    1 hour ago
















3












3








3





$begingroup$


# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in len(options):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer


I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?










share|improve this question









New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




# Standard multi choice question template
def multiChoiceQuestion(options: list):
while True:
print("nEnter the number of your choice - ")
for x in len(options):
print(str((x + 1)) + ". " + options[x])
print("n")
try:
answer = int(input())
except ValueError:
print("Doesn't seem like a number! Try again!")
continue
if answer < 1 or answer > len(options):
print("That option does not exist! Try again!")
continue
return answer


I created a template to ask a multi choice question in python. The loop will never reach it's end, since there is always a continue or a return statement. Is the while True condition appropriate for it?







python python-3.x validation






share|improve this question









New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 4 hours ago









200_success

130k16153419




130k16153419






New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 4 hours ago









HolyprogrammerHolyprogrammer

1428




1428




New contributor




Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Holyprogrammer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    "The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
    $endgroup$
    – Mast
    3 hours ago










  • $begingroup$
    Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
    $endgroup$
    – JDG
    1 hour ago




















  • $begingroup$
    "The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
    $endgroup$
    – Mast
    3 hours ago










  • $begingroup$
    Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
    $endgroup$
    – JDG
    1 hour ago


















$begingroup$
"The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
$endgroup$
– Mast
3 hours ago




$begingroup$
"The loop will never reach it's end ... Is the while True condition appropriate for it?" That depends on whether that is the intended behaviour. Is it?
$endgroup$
– Mast
3 hours ago












$begingroup$
Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
$endgroup$
– JDG
1 hour ago






$begingroup$
Side note: for x in len(options): will produce an error as Python doesn't allow iteration over an integer. 200_success's approach is the way to go here, but for future reference, use for x in range(len(options)): if you really need to loop a certain number of times. This takes the len(options) integer and creates an interable out of it.
$endgroup$
– JDG
1 hour ago












1 Answer
1






active

oldest

votes


















3












$begingroup$

The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.



PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.



The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.



def multi_choice_question(options: list):
while True:
print("nEnter the number of your choice - ")
for i, option in enumerate(options, 1):
print('{0}. {1}'.format(i, option))
print("n")
try:
answer = int(input())
if 1 <= answer <= len(options):
return answer
print("That option does not exist! Try again!")
except ValueError:
print("Doesn't seem like a number! Try again!")





share|improve this answer









$endgroup$













  • $begingroup$
    Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
    $endgroup$
    – JDG
    1 hour ago








  • 1




    $begingroup$
    @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
    $endgroup$
    – 200_success
    1 hour ago











Your Answer





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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3












$begingroup$

The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.



PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.



The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.



def multi_choice_question(options: list):
while True:
print("nEnter the number of your choice - ")
for i, option in enumerate(options, 1):
print('{0}. {1}'.format(i, option))
print("n")
try:
answer = int(input())
if 1 <= answer <= len(options):
return answer
print("That option does not exist! Try again!")
except ValueError:
print("Doesn't seem like a number! Try again!")





share|improve this answer









$endgroup$













  • $begingroup$
    Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
    $endgroup$
    – JDG
    1 hour ago








  • 1




    $begingroup$
    @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
    $endgroup$
    – 200_success
    1 hour ago
















3












$begingroup$

The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.



PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.



The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.



def multi_choice_question(options: list):
while True:
print("nEnter the number of your choice - ")
for i, option in enumerate(options, 1):
print('{0}. {1}'.format(i, option))
print("n")
try:
answer = int(input())
if 1 <= answer <= len(options):
return answer
print("That option does not exist! Try again!")
except ValueError:
print("Doesn't seem like a number! Try again!")





share|improve this answer









$endgroup$













  • $begingroup$
    Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
    $endgroup$
    – JDG
    1 hour ago








  • 1




    $begingroup$
    @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
    $endgroup$
    – 200_success
    1 hour ago














3












3








3





$begingroup$

The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.



PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.



The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.



def multi_choice_question(options: list):
while True:
print("nEnter the number of your choice - ")
for i, option in enumerate(options, 1):
print('{0}. {1}'.format(i, option))
print("n")
try:
answer = int(input())
if 1 <= answer <= len(options):
return answer
print("That option does not exist! Try again!")
except ValueError:
print("Doesn't seem like a number! Try again!")





share|improve this answer









$endgroup$



The while True is fine, and is probably the best way to do it. However, the rest of the flow control is a bit clumsy. By rearranging a few statements, you can eliminate the continues.



PEP 8, the official Python style guide, recommends lowercase_with_underscores for function names unless you have a good reason to deviate.



The loop to print the numbered menu would be better written using enumerate(). Also, Python supports double-ended comparisons for validating that the answer is in range.



def multi_choice_question(options: list):
while True:
print("nEnter the number of your choice - ")
for i, option in enumerate(options, 1):
print('{0}. {1}'.format(i, option))
print("n")
try:
answer = int(input())
if 1 <= answer <= len(options):
return answer
print("That option does not exist! Try again!")
except ValueError:
print("Doesn't seem like a number! Try again!")






share|improve this answer












share|improve this answer



share|improve this answer










answered 3 hours ago









200_success200_success

130k16153419




130k16153419












  • $begingroup$
    Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
    $endgroup$
    – JDG
    1 hour ago








  • 1




    $begingroup$
    @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
    $endgroup$
    – 200_success
    1 hour ago


















  • $begingroup$
    Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
    $endgroup$
    – JDG
    1 hour ago








  • 1




    $begingroup$
    @JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
    $endgroup$
    – 200_success
    1 hour ago
















$begingroup$
Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
$endgroup$
– JDG
1 hour ago






$begingroup$
Is it standard now in python 3.x to use f-strings? print(f'{i}. {option}')
$endgroup$
– JDG
1 hour ago






1




1




$begingroup$
@JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
$endgroup$
– 200_success
1 hour ago




$begingroup$
@JDG I wouldn't assume Python ≥ 3.6 if the question didn't specify it.
$endgroup$
– 200_success
1 hour ago










Holyprogrammer is a new contributor. Be nice, and check out our Code of Conduct.










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Holyprogrammer is a new contributor. Be nice, and check out our Code of Conduct.












Holyprogrammer is a new contributor. Be nice, and check out our Code of Conduct.
















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