Construct a section (or slice) through 3D RegionsIntersection of a MeshRegion and InfinitePlaneUnnecessary...
What will happen if Parliament votes "no" on each of the Brexit-related votes to be held on the 12th, 13th and 14th of March?
Why is it that Bernie Sanders is always called a "socialist"?
Play Zip, Zap, Zop
Current across a wire with zero potential difference
What happened to my GE option?
What is the difference between "...", '...', $'...', and $"..." quotes?
A Missing Symbol for This Logo
Looking for a specific 6502 Assembler
Why did Democrats in the Senate oppose the Born-Alive Abortion Survivors Protection Act?
Why is there a prohibition of gevinat aku"m?
How to visualize the Riemann-Roch theorem from complex analysis or geometric topology considerations?
How can the probability of a fumble decrease linearly with more dice?
How to make ice magic work from a scientific point of view?
What is the difference between rolling more dice versus fewer dice?
How does one write from a minority culture? A question on cultural references
Is there a verb that means to inject with poison?
Is using an 'empty' metaphor considered bad style?
Why do neural networks need so many training examples to perform?
How to not let the Identify spell spoil everything?
What happens when I Twin Life Transference?
What is the wife of a henpecked husband called?
A starship is travelling at 0.9c and collides with a small rock. Will it leave a clean hole through, or will more happen?
Building an exterior wall within an exterior wall for insulation
Boss asked me to sign a resignation paper without a date on it along with my new contract
Construct a section (or slice) through 3D Regions
Intersection of a MeshRegion and InfinitePlaneUnnecessary and slow conversion between simple polygons and geometric regionsDraw filled regions in DateListPlotRegionPlot not plotting some regionsHandling Self-Intersecting RegionsHow to plot the difference between two regions?Trouble with discrete MeshRegions: Integrating over plane slicesUsing RegionIntersection on Regions formed by RegionUnionRegionIntersection of RegionsRegions, Mesh Regions, and GraphicsRegionUnion for 3D Regions
$begingroup$
I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.
gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]

Now I define an InfinitePlane that I would like to slice through my regions.
ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]

How do I get the 2D Region lying in the plane? Is this possible?
This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.
Edit
@kglr suggest I can go further with ClipPanes. Here is his suggestion.
rc = RegionPlot3D[rr, ClipPlanes -> ip,
ClipPlanesStyle -> Opacity[0.1, Green]]

This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?
Edit 2
Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.
dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]

One can then extract the lines and reduce the coordinates to the values in the plane.
LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]

This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!
regions
$endgroup$
add a comment |
$begingroup$
I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.
gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]

Now I define an InfinitePlane that I would like to slice through my regions.
ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]

How do I get the 2D Region lying in the plane? Is this possible?
This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.
Edit
@kglr suggest I can go further with ClipPanes. Here is his suggestion.
rc = RegionPlot3D[rr, ClipPlanes -> ip,
ClipPlanesStyle -> Opacity[0.1, Green]]

This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?
Edit 2
Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.
dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]

One can then extract the lines and reduce the coordinates to the values in the plane.
LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]

This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!
regions
$endgroup$
$begingroup$
maybeRegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
$endgroup$
– kglr
5 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}]gives lines which can be further processed to form the polygons.
$endgroup$
– kglr
4 hours ago
add a comment |
$begingroup$
I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.
gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]

Now I define an InfinitePlane that I would like to slice through my regions.
ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]

How do I get the 2D Region lying in the plane? Is this possible?
This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.
Edit
@kglr suggest I can go further with ClipPanes. Here is his suggestion.
rc = RegionPlot3D[rr, ClipPlanes -> ip,
ClipPlanesStyle -> Opacity[0.1, Green]]

This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?
Edit 2
Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.
dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]

One can then extract the lines and reduce the coordinates to the values in the plane.
LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]

This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!
regions
$endgroup$
I would like to draw a section through some 3D regions. I start by making some simple 3D regions as a minimum working example.
gg = BoundaryDiscretizeGraphics[
Graphics3D[#]] & /@ {Cuboid[{-0.2, -0.5, 0}, {0.2, 0.5, 0.5}],
Cone[{{1.5, 0, 0}, {2, 0, 2}}, 0.1] ,
Cylinder[{{2, 0, 1}, {3, 0, 0.5}}, 0.1], Sphere[{3, 0, 0}, 0.3],
Tube[{{0, 0, 0}, {4, 0, 3}}, 0.03]};
rr = RegionUnion[gg, Boxed -> True]

Now I define an InfinitePlane that I would like to slice through my regions.
ip = InfinitePlane[{{0, 0, 0}, {4, 0, 0}, {4, 0, 1}}];
Show[
Graphics3D[ip],
Region[rr]
]

How do I get the 2D Region lying in the plane? Is this possible?
This post has an approach for 3D primitives but I can't see how to extend this to 3D regions.
Edit
@kglr suggest I can go further with ClipPanes. Here is his suggestion.
rc = RegionPlot3D[rr, ClipPlanes -> ip,
ClipPlanesStyle -> Opacity[0.1, Green]]

This does the slicing and shows the insides but does not give me 2D regions. Could this be a starting point?
Edit 2
Continuing to take instructions from @kglr (see comments). He suggests finding the intersection with the mesh primitives.
dg = DiscretizeGraphics@
Quiet@Graphics3D[{DeleteCases[
RegionIntersection[ip, #] & /@
MeshPrimitives[rr,
2], _EmptyRegion | _Point | _RegionIntersection]}]

One can then extract the lines and reduce the coordinates to the values in the plane.
LL = MeshPrimitives[dg, 1] /. {a_, b_, c_} -> {a, c};
Graphics[LL]

This works. I will have to think further about what to do if the plane is not aligned with an axis. Reducing to 2D coordinates will then have to be done by a coordinate transform. However this is considerable progress and @kglr didn't have to post an answer!
regions
regions
edited 4 hours ago
Hugh
asked 5 hours ago
HughHugh
6,39521945
6,39521945
$begingroup$
maybeRegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
$endgroup$
– kglr
5 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}]gives lines which can be further processed to form the polygons.
$endgroup$
– kglr
4 hours ago
add a comment |
$begingroup$
maybeRegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?
$endgroup$
– kglr
5 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}]gives lines which can be further processed to form the polygons.
$endgroup$
– kglr
4 hours ago
$begingroup$
maybe
RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?$endgroup$
– kglr
5 hours ago
$begingroup$
maybe
RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?$endgroup$
– kglr
5 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}] gives lines which can be further processed to form the polygons.$endgroup$
– kglr
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}] gives lines which can be further processed to form the polygons.$endgroup$
– kglr
4 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.
Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:
cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

We can easily project to 2d as well:
BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]

We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.
halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;
halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr
halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];
halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];
clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;
InverseTransformedRegion[clip, rt]
]
halfSpaceClip[___] = $Failed;
The same example:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

A non axes aligned plane:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

$endgroup$
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
4 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f192263%2fconstruct-a-section-or-slice-through-3d-regions%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.
Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:
cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

We can easily project to 2d as well:
BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]

We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.
halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;
halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr
halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];
halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];
clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;
InverseTransformedRegion[clip, rt]
]
halfSpaceClip[___] = $Failed;
The same example:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

A non axes aligned plane:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

$endgroup$
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
4 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
add a comment |
$begingroup$
Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.
Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:
cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

We can easily project to 2d as well:
BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]

We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.
halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;
halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr
halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];
halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];
clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;
InverseTransformedRegion[clip, rt]
]
halfSpaceClip[___] = $Failed;
The same example:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

A non axes aligned plane:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

$endgroup$
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
4 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
add a comment |
$begingroup$
Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.
Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:
cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

We can easily project to 2d as well:
BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]

We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.
halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;
halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr
halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];
halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];
clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;
InverseTransformedRegion[clip, rt]
]
halfSpaceClip[___] = $Failed;
The same example:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

A non axes aligned plane:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

$endgroup$
Note that RegionIntersection[rr, ip] should give you what you want here but doesn't.
Since we have an axes aligned plane, we can workaround this by exploiting the second argument of DiscretizeRegion:
cut = DiscretizeRegion[RegionBoundary[rr], {{-0.2`, 4.1`}, {-0.5`, 0}, {-0.3`, 3.1`}}];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

We can easily project to 2d as well:
BoundaryMeshRegion[MeshCoordinates[cut][[All, {1, 3}]], holes]

We can adapt this idea to any plane. I'll use HalfSpace to emphasize which side of the plane is kept.
halfSpaceClip[reg_, ___] /; !MeshRegionQ[reg] && !BoundaryMeshRegionQ[reg] && RegionEmbeddingDimension[reg] != 3 = $Failed;
halfSpaceClip[mr_, h_HalfSpace] /; RegionWithin[h, mr] := mr
halfSpaceClip[mr_, HalfSpace[n_, p_]] /; RegionWithin[HalfSpace[-n, p], mr] = EmptyRegion[3];
halfSpaceClip[mr_, HalfSpace[n_, p_]] :=
Block[{rt, rot, bds, clip},
rt = RotationTransform[{n, {0, 0, -1}}, p];
rot = TransformedRegion[mr, rt];
bds = RegionBounds[rot];
clip = DiscretizeRegion[rot, {#1+5{-1,1}, #2+5{-1,1}, {p[[3]], #3[[2]]+5}}]& @@ bds;
InverseTransformedRegion[clip, rt]
]
halfSpaceClip[___] = $Failed;
The same example:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{0, 1, 0}, {0, 0, 0}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

A non axes aligned plane:
cut = halfSpaceClip[RegionBoundary[rr], HalfSpace[{.5, 1, -1}, {0, .5, .5}]];
holes = FindMeshDefects[cut, "HoleEdges", "Cell"]["HoleEdges"];
slice = MeshRegion[MeshCoordinates[cut], holes, PlotTheme -> "Lines",
MeshCellStyle -> {1 -> Black}];
Show[slice, BoundaryMeshRegion[rr, BaseStyle -> Opacity[.3]]]

edited 3 hours ago
answered 4 hours ago
Chip HurstChip Hurst
21.8k15790
21.8k15790
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
4 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
add a comment |
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
4 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
4 hours ago
$begingroup$
Thanks. This works. How do you deal with a plane not aligned with the axis? Is a coordinate transformation of the axis is needed?
$endgroup$
– Hugh
4 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
@Hugh Yes that is one way. See my latest edit.
$endgroup$
– Chip Hurst
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
$begingroup$
Excellent many thanks.
$endgroup$
– Hugh
3 hours ago
add a comment |
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f192263%2fconstruct-a-section-or-slice-through-3d-regions%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
maybe
RegionPlot3D[rr, ClipPlanes -> ip, ClipPlanesStyle -> Opacity[.5, Red]]?$endgroup$
– kglr
5 hours ago
$begingroup$
@kglr Thanks. This gives me a nice slice but how do I extract the lines on the plane and form regions?
$endgroup$
– Hugh
4 hours ago
$begingroup$
dg = DiscretizeGraphics@ Quiet@Graphics3D[{DeleteCases[ RegionIntersection[ip, #] & /@ MeshPrimitives[rr, 2], _EmptyRegion | _Point | _RegionIntersection]}]gives lines which can be further processed to form the polygons.$endgroup$
– kglr
4 hours ago