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How to apply outer limit offset and filters in the subquery to avoid grouping over the complete table used in subquery in Postgresql


Subqueries run very fast individually, but when joined are very slowGroup By primary key or DISTINCT increase query time over 1000x with limitNeed to find the employees who have switched jobs atleast twiceHow to INNER JOIN and OUTER JOIN within the same table?Effect of where statement in subquery (to get rid of unnecessary join)Filtering UNION ALL result is much slower than filtering each subqueryCan I make this multiple join query faster?Check for existing matches to find the field their grouped-byMissing date handling between subquery and OUTER APPLYCounting and grouping over multiple OUTER JOINs













0















I have legacy tables similar to the following:



employee



------------------------------------
| employee_id | name
------------------------------------
| 1 | David
| 2 | Mathew
------------------------------------


payroll



-------------------------------------
| employee_id | salary
-------------------------------------
| 2 | 200000
| 3 | 90000
-------------------------------------


I want to get the following data, after joins and filters:



-----------------------------------------------------------
| address_id | employee_id | address
-----------------------------------------------------------
| 1 | 2 | street 1, NY
| 2 | 2 | street 2, DC
------------------------------------------------------------


I have the following query:



SELECT employee_id, salary, address_arr 
FROM employee
LEFT JOIN payroll on payroll.employee_id = employee.employee_id
INNER JOIN
(
SELECT employee_id, ARRAY_AGG(address) as address_arr
FROM addresses
GROUP BY employee_id
) table_address ON table_address.employee_id = employee.employee_id
WHERE employee.employee_id < 1000000
LIMIT 100
OFFSET 0


Above query gives the desired output but is highly unoptimized as the GROUP BY operation occurs over the complete addresses table before being used for JOIN operation the outer query.



Kindly answer:




  1. How can we avoid the GROUP BY operation to occurs over the complete
    addresses table by using LIMIT OFFSET of the outer query?

  2. Will the condition WHERE employee.employee_id < 1000000 be applied on subquery before or after the GROUP BY operation in the inner query. If the condition is applied after the GROUP BY, how can we avoid that?


Note: There are multiple JOINs and subqueries in the actual query being used.










share|improve this question

























  • PS. LIMIT without ORDER BY gives you 100 random records from the whole data array... do you really need in that?

    – Akina
    Feb 8 at 7:44











  • You should present us the simplest query you can which still have the issue. If you remove the left join on PAYROLL, does the problem go away?

    – jjanes
    Feb 9 at 15:18
















0















I have legacy tables similar to the following:



employee



------------------------------------
| employee_id | name
------------------------------------
| 1 | David
| 2 | Mathew
------------------------------------


payroll



-------------------------------------
| employee_id | salary
-------------------------------------
| 2 | 200000
| 3 | 90000
-------------------------------------


I want to get the following data, after joins and filters:



-----------------------------------------------------------
| address_id | employee_id | address
-----------------------------------------------------------
| 1 | 2 | street 1, NY
| 2 | 2 | street 2, DC
------------------------------------------------------------


I have the following query:



SELECT employee_id, salary, address_arr 
FROM employee
LEFT JOIN payroll on payroll.employee_id = employee.employee_id
INNER JOIN
(
SELECT employee_id, ARRAY_AGG(address) as address_arr
FROM addresses
GROUP BY employee_id
) table_address ON table_address.employee_id = employee.employee_id
WHERE employee.employee_id < 1000000
LIMIT 100
OFFSET 0


Above query gives the desired output but is highly unoptimized as the GROUP BY operation occurs over the complete addresses table before being used for JOIN operation the outer query.



Kindly answer:




  1. How can we avoid the GROUP BY operation to occurs over the complete
    addresses table by using LIMIT OFFSET of the outer query?

  2. Will the condition WHERE employee.employee_id < 1000000 be applied on subquery before or after the GROUP BY operation in the inner query. If the condition is applied after the GROUP BY, how can we avoid that?


Note: There are multiple JOINs and subqueries in the actual query being used.










share|improve this question

























  • PS. LIMIT without ORDER BY gives you 100 random records from the whole data array... do you really need in that?

    – Akina
    Feb 8 at 7:44











  • You should present us the simplest query you can which still have the issue. If you remove the left join on PAYROLL, does the problem go away?

    – jjanes
    Feb 9 at 15:18














0












0








0








I have legacy tables similar to the following:



employee



------------------------------------
| employee_id | name
------------------------------------
| 1 | David
| 2 | Mathew
------------------------------------


payroll



-------------------------------------
| employee_id | salary
-------------------------------------
| 2 | 200000
| 3 | 90000
-------------------------------------


I want to get the following data, after joins and filters:



-----------------------------------------------------------
| address_id | employee_id | address
-----------------------------------------------------------
| 1 | 2 | street 1, NY
| 2 | 2 | street 2, DC
------------------------------------------------------------


I have the following query:



SELECT employee_id, salary, address_arr 
FROM employee
LEFT JOIN payroll on payroll.employee_id = employee.employee_id
INNER JOIN
(
SELECT employee_id, ARRAY_AGG(address) as address_arr
FROM addresses
GROUP BY employee_id
) table_address ON table_address.employee_id = employee.employee_id
WHERE employee.employee_id < 1000000
LIMIT 100
OFFSET 0


Above query gives the desired output but is highly unoptimized as the GROUP BY operation occurs over the complete addresses table before being used for JOIN operation the outer query.



Kindly answer:




  1. How can we avoid the GROUP BY operation to occurs over the complete
    addresses table by using LIMIT OFFSET of the outer query?

  2. Will the condition WHERE employee.employee_id < 1000000 be applied on subquery before or after the GROUP BY operation in the inner query. If the condition is applied after the GROUP BY, how can we avoid that?


Note: There are multiple JOINs and subqueries in the actual query being used.










share|improve this question
















I have legacy tables similar to the following:



employee



------------------------------------
| employee_id | name
------------------------------------
| 1 | David
| 2 | Mathew
------------------------------------


payroll



-------------------------------------
| employee_id | salary
-------------------------------------
| 2 | 200000
| 3 | 90000
-------------------------------------


I want to get the following data, after joins and filters:



-----------------------------------------------------------
| address_id | employee_id | address
-----------------------------------------------------------
| 1 | 2 | street 1, NY
| 2 | 2 | street 2, DC
------------------------------------------------------------


I have the following query:



SELECT employee_id, salary, address_arr 
FROM employee
LEFT JOIN payroll on payroll.employee_id = employee.employee_id
INNER JOIN
(
SELECT employee_id, ARRAY_AGG(address) as address_arr
FROM addresses
GROUP BY employee_id
) table_address ON table_address.employee_id = employee.employee_id
WHERE employee.employee_id < 1000000
LIMIT 100
OFFSET 0


Above query gives the desired output but is highly unoptimized as the GROUP BY operation occurs over the complete addresses table before being used for JOIN operation the outer query.



Kindly answer:




  1. How can we avoid the GROUP BY operation to occurs over the complete
    addresses table by using LIMIT OFFSET of the outer query?

  2. Will the condition WHERE employee.employee_id < 1000000 be applied on subquery before or after the GROUP BY operation in the inner query. If the condition is applied after the GROUP BY, how can we avoid that?


Note: There are multiple JOINs and subqueries in the actual query being used.







postgresql join postgresql-performance group-by subquery






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Feb 8 at 7:20







nimeshkiranverma

















asked Feb 8 at 7:04









nimeshkiranvermanimeshkiranverma

1013




1013













  • PS. LIMIT without ORDER BY gives you 100 random records from the whole data array... do you really need in that?

    – Akina
    Feb 8 at 7:44











  • You should present us the simplest query you can which still have the issue. If you remove the left join on PAYROLL, does the problem go away?

    – jjanes
    Feb 9 at 15:18



















  • PS. LIMIT without ORDER BY gives you 100 random records from the whole data array... do you really need in that?

    – Akina
    Feb 8 at 7:44











  • You should present us the simplest query you can which still have the issue. If you remove the left join on PAYROLL, does the problem go away?

    – jjanes
    Feb 9 at 15:18

















PS. LIMIT without ORDER BY gives you 100 random records from the whole data array... do you really need in that?

– Akina
Feb 8 at 7:44





PS. LIMIT without ORDER BY gives you 100 random records from the whole data array... do you really need in that?

– Akina
Feb 8 at 7:44













You should present us the simplest query you can which still have the issue. If you remove the left join on PAYROLL, does the problem go away?

– jjanes
Feb 9 at 15:18





You should present us the simplest query you can which still have the issue. If you remove the left join on PAYROLL, does the problem go away?

– jjanes
Feb 9 at 15:18










3 Answers
3






active

oldest

votes


















2














I am not sure if this is really more efficient, but you could try to join to a derived table that applies the limit.



select emp.employee_id, emp.salary, adr.address_arr 
from (
SELECT employee_id, salary, address_arr
FROM employee
LEFT JOIN payroll on payroll.employee_id = employee.employee_id
WHERE employee.employee_id < 1000000
LIMIT 100
OFFSET 0
) as emp
JOIN (
SELECT a.employee_id, ARRAY_AGG(a.address) as address_arr
FROM addresses a
GROUP BY employee_id
) as adr ON adr.employee_id = emp.employee_id;


The first derived table only selects 100 rows, and the join/group by should then only be done for those 100 employees.



If the optimizer doesn't push that down, you could try a lateral join instead to "force" a push down:



select emp.employee_id, emp.salary, adr.address_arr 
from (
SELECT employee_id, salary, address_arr
FROM employee
LEFT JOIN payroll on payroll.employee_id = employee.employee_id
WHERE employee.employee_id < 1000000
LIMIT 100
OFFSET 0
) as emp
LATERAL JOIN (
SELECT a.employee_id, ARRAY_AGG(a.address) as address_arr
FROM addresses a
WHERE a.employee_id = emp.employee_id
GROUP BY employee_id
) as adr ON adr.employee_id = emp.employee_id;


The join condition isn't really needed, but it dosn't hurt either






share|improve this answer































    0














    Maybe



    SELECT employee.employee_id, payroll.salary, ARRAY_AGG(addresses.address)
    FROM employee
    INNER JOIN addresses ON addresses.employee_id = employee.employee_id
    LEFT JOIN payroll on payroll.employee_id = employee.employee_id
    WHERE employee.employee_id < 1000000
    GROUP BY employee.employee_id
    LIMIT 100
    OFFSET 0


    ?



    And - do you really need in records where no appropriate records in payroll table which leads to NULLs in payroll.salary? Maybe, INNER JOIN is enough?






    share|improve this answer


























    • The query is incorrect. payroll.salary needs to be included in GROUP BY clause, which will unoptimise the query further

      – nimeshkiranverma
      Feb 8 at 7:48











    • @nimeshkiranverma payroll.salary needs to be included in GROUP BY clause you may wrap it using any aggregate function which can be applied to this field datatype.

      – Akina
      Feb 8 at 7:50



















    0














    I am new to this and had some help , here's what I came up with:



    with t as (SELECT employee.employee_id, salary  FROM employee  LEFT JOIN payroll on payroll.employee_id = employee.employee_id WHERE employee.employee_id < 1000000 LIMIT 100 OFFSET 0)
    select t.employee_id, max(t.salary), ARRAY_AGG(address) as address_arr from address left join t on address.employee_id = t.employee_id where address.employee_id = t.employee_id group by t.employee_id;


    explain analyze yields



    enter image description here






    share|improve this answer








    New contributor




    Rahul Ahuja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.




















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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2














      I am not sure if this is really more efficient, but you could try to join to a derived table that applies the limit.



      select emp.employee_id, emp.salary, adr.address_arr 
      from (
      SELECT employee_id, salary, address_arr
      FROM employee
      LEFT JOIN payroll on payroll.employee_id = employee.employee_id
      WHERE employee.employee_id < 1000000
      LIMIT 100
      OFFSET 0
      ) as emp
      JOIN (
      SELECT a.employee_id, ARRAY_AGG(a.address) as address_arr
      FROM addresses a
      GROUP BY employee_id
      ) as adr ON adr.employee_id = emp.employee_id;


      The first derived table only selects 100 rows, and the join/group by should then only be done for those 100 employees.



      If the optimizer doesn't push that down, you could try a lateral join instead to "force" a push down:



      select emp.employee_id, emp.salary, adr.address_arr 
      from (
      SELECT employee_id, salary, address_arr
      FROM employee
      LEFT JOIN payroll on payroll.employee_id = employee.employee_id
      WHERE employee.employee_id < 1000000
      LIMIT 100
      OFFSET 0
      ) as emp
      LATERAL JOIN (
      SELECT a.employee_id, ARRAY_AGG(a.address) as address_arr
      FROM addresses a
      WHERE a.employee_id = emp.employee_id
      GROUP BY employee_id
      ) as adr ON adr.employee_id = emp.employee_id;


      The join condition isn't really needed, but it dosn't hurt either






      share|improve this answer




























        2














        I am not sure if this is really more efficient, but you could try to join to a derived table that applies the limit.



        select emp.employee_id, emp.salary, adr.address_arr 
        from (
        SELECT employee_id, salary, address_arr
        FROM employee
        LEFT JOIN payroll on payroll.employee_id = employee.employee_id
        WHERE employee.employee_id < 1000000
        LIMIT 100
        OFFSET 0
        ) as emp
        JOIN (
        SELECT a.employee_id, ARRAY_AGG(a.address) as address_arr
        FROM addresses a
        GROUP BY employee_id
        ) as adr ON adr.employee_id = emp.employee_id;


        The first derived table only selects 100 rows, and the join/group by should then only be done for those 100 employees.



        If the optimizer doesn't push that down, you could try a lateral join instead to "force" a push down:



        select emp.employee_id, emp.salary, adr.address_arr 
        from (
        SELECT employee_id, salary, address_arr
        FROM employee
        LEFT JOIN payroll on payroll.employee_id = employee.employee_id
        WHERE employee.employee_id < 1000000
        LIMIT 100
        OFFSET 0
        ) as emp
        LATERAL JOIN (
        SELECT a.employee_id, ARRAY_AGG(a.address) as address_arr
        FROM addresses a
        WHERE a.employee_id = emp.employee_id
        GROUP BY employee_id
        ) as adr ON adr.employee_id = emp.employee_id;


        The join condition isn't really needed, but it dosn't hurt either






        share|improve this answer


























          2












          2








          2







          I am not sure if this is really more efficient, but you could try to join to a derived table that applies the limit.



          select emp.employee_id, emp.salary, adr.address_arr 
          from (
          SELECT employee_id, salary, address_arr
          FROM employee
          LEFT JOIN payroll on payroll.employee_id = employee.employee_id
          WHERE employee.employee_id < 1000000
          LIMIT 100
          OFFSET 0
          ) as emp
          JOIN (
          SELECT a.employee_id, ARRAY_AGG(a.address) as address_arr
          FROM addresses a
          GROUP BY employee_id
          ) as adr ON adr.employee_id = emp.employee_id;


          The first derived table only selects 100 rows, and the join/group by should then only be done for those 100 employees.



          If the optimizer doesn't push that down, you could try a lateral join instead to "force" a push down:



          select emp.employee_id, emp.salary, adr.address_arr 
          from (
          SELECT employee_id, salary, address_arr
          FROM employee
          LEFT JOIN payroll on payroll.employee_id = employee.employee_id
          WHERE employee.employee_id < 1000000
          LIMIT 100
          OFFSET 0
          ) as emp
          LATERAL JOIN (
          SELECT a.employee_id, ARRAY_AGG(a.address) as address_arr
          FROM addresses a
          WHERE a.employee_id = emp.employee_id
          GROUP BY employee_id
          ) as adr ON adr.employee_id = emp.employee_id;


          The join condition isn't really needed, but it dosn't hurt either






          share|improve this answer













          I am not sure if this is really more efficient, but you could try to join to a derived table that applies the limit.



          select emp.employee_id, emp.salary, adr.address_arr 
          from (
          SELECT employee_id, salary, address_arr
          FROM employee
          LEFT JOIN payroll on payroll.employee_id = employee.employee_id
          WHERE employee.employee_id < 1000000
          LIMIT 100
          OFFSET 0
          ) as emp
          JOIN (
          SELECT a.employee_id, ARRAY_AGG(a.address) as address_arr
          FROM addresses a
          GROUP BY employee_id
          ) as adr ON adr.employee_id = emp.employee_id;


          The first derived table only selects 100 rows, and the join/group by should then only be done for those 100 employees.



          If the optimizer doesn't push that down, you could try a lateral join instead to "force" a push down:



          select emp.employee_id, emp.salary, adr.address_arr 
          from (
          SELECT employee_id, salary, address_arr
          FROM employee
          LEFT JOIN payroll on payroll.employee_id = employee.employee_id
          WHERE employee.employee_id < 1000000
          LIMIT 100
          OFFSET 0
          ) as emp
          LATERAL JOIN (
          SELECT a.employee_id, ARRAY_AGG(a.address) as address_arr
          FROM addresses a
          WHERE a.employee_id = emp.employee_id
          GROUP BY employee_id
          ) as adr ON adr.employee_id = emp.employee_id;


          The join condition isn't really needed, but it dosn't hurt either







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Feb 8 at 7:41









          a_horse_with_no_namea_horse_with_no_name

          40.1k776112




          40.1k776112

























              0














              Maybe



              SELECT employee.employee_id, payroll.salary, ARRAY_AGG(addresses.address)
              FROM employee
              INNER JOIN addresses ON addresses.employee_id = employee.employee_id
              LEFT JOIN payroll on payroll.employee_id = employee.employee_id
              WHERE employee.employee_id < 1000000
              GROUP BY employee.employee_id
              LIMIT 100
              OFFSET 0


              ?



              And - do you really need in records where no appropriate records in payroll table which leads to NULLs in payroll.salary? Maybe, INNER JOIN is enough?






              share|improve this answer


























              • The query is incorrect. payroll.salary needs to be included in GROUP BY clause, which will unoptimise the query further

                – nimeshkiranverma
                Feb 8 at 7:48











              • @nimeshkiranverma payroll.salary needs to be included in GROUP BY clause you may wrap it using any aggregate function which can be applied to this field datatype.

                – Akina
                Feb 8 at 7:50
















              0














              Maybe



              SELECT employee.employee_id, payroll.salary, ARRAY_AGG(addresses.address)
              FROM employee
              INNER JOIN addresses ON addresses.employee_id = employee.employee_id
              LEFT JOIN payroll on payroll.employee_id = employee.employee_id
              WHERE employee.employee_id < 1000000
              GROUP BY employee.employee_id
              LIMIT 100
              OFFSET 0


              ?



              And - do you really need in records where no appropriate records in payroll table which leads to NULLs in payroll.salary? Maybe, INNER JOIN is enough?






              share|improve this answer


























              • The query is incorrect. payroll.salary needs to be included in GROUP BY clause, which will unoptimise the query further

                – nimeshkiranverma
                Feb 8 at 7:48











              • @nimeshkiranverma payroll.salary needs to be included in GROUP BY clause you may wrap it using any aggregate function which can be applied to this field datatype.

                – Akina
                Feb 8 at 7:50














              0












              0








              0







              Maybe



              SELECT employee.employee_id, payroll.salary, ARRAY_AGG(addresses.address)
              FROM employee
              INNER JOIN addresses ON addresses.employee_id = employee.employee_id
              LEFT JOIN payroll on payroll.employee_id = employee.employee_id
              WHERE employee.employee_id < 1000000
              GROUP BY employee.employee_id
              LIMIT 100
              OFFSET 0


              ?



              And - do you really need in records where no appropriate records in payroll table which leads to NULLs in payroll.salary? Maybe, INNER JOIN is enough?






              share|improve this answer















              Maybe



              SELECT employee.employee_id, payroll.salary, ARRAY_AGG(addresses.address)
              FROM employee
              INNER JOIN addresses ON addresses.employee_id = employee.employee_id
              LEFT JOIN payroll on payroll.employee_id = employee.employee_id
              WHERE employee.employee_id < 1000000
              GROUP BY employee.employee_id
              LIMIT 100
              OFFSET 0


              ?



              And - do you really need in records where no appropriate records in payroll table which leads to NULLs in payroll.salary? Maybe, INNER JOIN is enough?







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Feb 8 at 7:21

























              answered Feb 8 at 7:15









              AkinaAkina

              4,0461311




              4,0461311













              • The query is incorrect. payroll.salary needs to be included in GROUP BY clause, which will unoptimise the query further

                – nimeshkiranverma
                Feb 8 at 7:48











              • @nimeshkiranverma payroll.salary needs to be included in GROUP BY clause you may wrap it using any aggregate function which can be applied to this field datatype.

                – Akina
                Feb 8 at 7:50



















              • The query is incorrect. payroll.salary needs to be included in GROUP BY clause, which will unoptimise the query further

                – nimeshkiranverma
                Feb 8 at 7:48











              • @nimeshkiranverma payroll.salary needs to be included in GROUP BY clause you may wrap it using any aggregate function which can be applied to this field datatype.

                – Akina
                Feb 8 at 7:50

















              The query is incorrect. payroll.salary needs to be included in GROUP BY clause, which will unoptimise the query further

              – nimeshkiranverma
              Feb 8 at 7:48





              The query is incorrect. payroll.salary needs to be included in GROUP BY clause, which will unoptimise the query further

              – nimeshkiranverma
              Feb 8 at 7:48













              @nimeshkiranverma payroll.salary needs to be included in GROUP BY clause you may wrap it using any aggregate function which can be applied to this field datatype.

              – Akina
              Feb 8 at 7:50





              @nimeshkiranverma payroll.salary needs to be included in GROUP BY clause you may wrap it using any aggregate function which can be applied to this field datatype.

              – Akina
              Feb 8 at 7:50











              0














              I am new to this and had some help , here's what I came up with:



              with t as (SELECT employee.employee_id, salary  FROM employee  LEFT JOIN payroll on payroll.employee_id = employee.employee_id WHERE employee.employee_id < 1000000 LIMIT 100 OFFSET 0)
              select t.employee_id, max(t.salary), ARRAY_AGG(address) as address_arr from address left join t on address.employee_id = t.employee_id where address.employee_id = t.employee_id group by t.employee_id;


              explain analyze yields



              enter image description here






              share|improve this answer








              New contributor




              Rahul Ahuja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.

























                0














                I am new to this and had some help , here's what I came up with:



                with t as (SELECT employee.employee_id, salary  FROM employee  LEFT JOIN payroll on payroll.employee_id = employee.employee_id WHERE employee.employee_id < 1000000 LIMIT 100 OFFSET 0)
                select t.employee_id, max(t.salary), ARRAY_AGG(address) as address_arr from address left join t on address.employee_id = t.employee_id where address.employee_id = t.employee_id group by t.employee_id;


                explain analyze yields



                enter image description here






                share|improve this answer








                New contributor




                Rahul Ahuja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.























                  0












                  0








                  0







                  I am new to this and had some help , here's what I came up with:



                  with t as (SELECT employee.employee_id, salary  FROM employee  LEFT JOIN payroll on payroll.employee_id = employee.employee_id WHERE employee.employee_id < 1000000 LIMIT 100 OFFSET 0)
                  select t.employee_id, max(t.salary), ARRAY_AGG(address) as address_arr from address left join t on address.employee_id = t.employee_id where address.employee_id = t.employee_id group by t.employee_id;


                  explain analyze yields



                  enter image description here






                  share|improve this answer








                  New contributor




                  Rahul Ahuja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.










                  I am new to this and had some help , here's what I came up with:



                  with t as (SELECT employee.employee_id, salary  FROM employee  LEFT JOIN payroll on payroll.employee_id = employee.employee_id WHERE employee.employee_id < 1000000 LIMIT 100 OFFSET 0)
                  select t.employee_id, max(t.salary), ARRAY_AGG(address) as address_arr from address left join t on address.employee_id = t.employee_id where address.employee_id = t.employee_id group by t.employee_id;


                  explain analyze yields



                  enter image description here







                  share|improve this answer








                  New contributor




                  Rahul Ahuja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  share|improve this answer



                  share|improve this answer






                  New contributor




                  Rahul Ahuja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  answered 13 mins ago









                  Rahul AhujaRahul Ahuja

                  1




                  1




                  New contributor




                  Rahul Ahuja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.





                  New contributor





                  Rahul Ahuja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






                  Rahul Ahuja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






























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