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The No-Straight Maze
The Origins of a Confusing MazeEdward's Maze IA-maze-ing WordsearchAlice and the Fractal Hedge MazeA-maze-ing TilesCryptic Clue MazeHelp me to find a small but hard and clever mazeCreate a changeable mazeNodes & TunnelsMore Nodes & Tunnels - The Tower
$begingroup$
Consider the following maze.
You can walk on the black lines, and your aim is to go from the green at the maze's bottom to the red on the left side. However, each time you reach an intersection of three or more black paths (spokes), you must turn 90 degrees either direction, rather than continuing straight.
Find a valid path through the maze, or prove that no such solution exists.
- It's not a lateral-thinking puzzle; the solution is not a trick.
- If you arrive at a corner, simply follow the path.
- You cannot suddenly turn around and walk the other way, but you may retrace your steps otherwise.
- It's a puzzle of my own creation, and I already have the solution.
- The missing line in the middle of the maze is intentional.
logical-deduction no-computers mazes
asked 1 hour ago
ZanyGZanyG
844317
$endgroup$
add a comment |
$begingroup$
Consider the following maze.
You can walk on the black lines, and your aim is to go from the green at the maze's bottom to the red on the left side. However, each time you reach an intersection of three or more black paths (spokes), you must turn 90 degrees either direction, rather than continuing straight.
Find a valid path through the maze, or prove that no such solution exists.
- It's not a lateral-thinking puzzle; the solution is not a trick.
- If you arrive at a corner, simply follow the path.
- You cannot suddenly turn around and walk the other way, but you may retrace your steps otherwise.
- It's a puzzle of my own creation, and I already have the solution.
- The missing line in the middle of the maze is intentional.
logical-deduction no-computers mazes
asked 1 hour ago
ZanyGZanyG
844317
$endgroup$
add a comment |
$begingroup$
Consider the following maze.
You can walk on the black lines, and your aim is to go from the green at the maze's bottom to the red on the left side. However, each time you reach an intersection of three or more black paths (spokes), you must turn 90 degrees either direction, rather than continuing straight.
Find a valid path through the maze, or prove that no such solution exists.
- It's not a lateral-thinking puzzle; the solution is not a trick.
- If you arrive at a corner, simply follow the path.
- You cannot suddenly turn around and walk the other way, but you may retrace your steps otherwise.
- It's a puzzle of my own creation, and I already have the solution.
- The missing line in the middle of the maze is intentional.
logical-deduction no-computers mazes
asked 1 hour ago
ZanyGZanyG
844317
$endgroup$
Consider the following maze.
You can walk on the black lines, and your aim is to go from the green at the maze's bottom to the red on the left side. However, each time you reach an intersection of three or more black paths (spokes), you must turn 90 degrees either direction, rather than continuing straight.
Find a valid path through the maze, or prove that no such solution exists.
- It's not a lateral-thinking puzzle; the solution is not a trick.
- If you arrive at a corner, simply follow the path.
- You cannot suddenly turn around and walk the other way, but you may retrace your steps otherwise.
- It's a puzzle of my own creation, and I already have the solution.
- The missing line in the middle of the maze is intentional.
logical-deduction no-computers mazes
logical-deduction no-computers mazes
asked 1 hour ago
ZanyGZanyG
844317
asked 1 hour ago
ZanyGZanyG
844317
asked 1 hour ago
ZanyGZanyG
844317
asked 1 hour ago
ZanyGZanyG
844317
asked 1 hour ago
ZanyGZanyG
844317
844317
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Since we must always turn 90 degrees, every odd-numbered step we take is always vertical and every even-numbered step is horizontal. Since the last step has to be horizontal, it means our total path has to be an even number of steps. In other words, once we've reached the red squares, we have made the same amount of vertical and horizontal steps.
After each odd-numbered vertical step, we are an odd number of rows away from the starting point. After each even-numbered step, we are an even number of rows away. The same applies for horizontal steps.
In the end, we have taken the same number of steps both horizontally and vertically (i.e. either both are even or both are odd). We are 4 columns away from the starting point, so we must have taken an even number of horizontal steps. However, we are 5 rows away from the starting point, so we must have taken an odd number of vertical steps. This is impossible, so we can conclude that there is no such path through the maze.
answered 44 mins ago
jafejafe
21k458212
$endgroup$
$begingroup$
Very good; exactly what I had in mind. I'll wait a bit before accepting.
$endgroup$
– ZanyG
42 mins ago
add a comment |
$begingroup$
The path through the maze is:
non-existent.
Some notes about this -
The design of the maze is such that you'll basically be turning after following any line.
The missing segment is largely irrelevant.
Each step north, including the first, requires the next step to be east or west. Likewise for any step south.
You have to travel a net distance north of 5 steps.
After 1 step north + 1 step east/west, you're an ODD number of steps east or west of the starting position.
After two steps north + 1 east/west, you'll be an EVEN number of steps east or west of the start.
...
On a turn that leaves you 5 steps north, no matter how you get there, you'll be an even number of steps from the origin and about to have to turn east or west. The end state would require you to be an odd (3) number of steps west, so you will never be able to exit there.
answered 42 mins ago
Rubio♦Rubio
28.8k565178
$endgroup$
add a comment |
Your Answer
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Since we must always turn 90 degrees, every odd-numbered step we take is always vertical and every even-numbered step is horizontal. Since the last step has to be horizontal, it means our total path has to be an even number of steps. In other words, once we've reached the red squares, we have made the same amount of vertical and horizontal steps.
After each odd-numbered vertical step, we are an odd number of rows away from the starting point. After each even-numbered step, we are an even number of rows away. The same applies for horizontal steps.
In the end, we have taken the same number of steps both horizontally and vertically (i.e. either both are even or both are odd). We are 4 columns away from the starting point, so we must have taken an even number of horizontal steps. However, we are 5 rows away from the starting point, so we must have taken an odd number of vertical steps. This is impossible, so we can conclude that there is no such path through the maze.
answered 44 mins ago
jafejafe
21k458212
$endgroup$
$begingroup$
Very good; exactly what I had in mind. I'll wait a bit before accepting.
$endgroup$
– ZanyG
42 mins ago
add a comment |
$begingroup$
Since we must always turn 90 degrees, every odd-numbered step we take is always vertical and every even-numbered step is horizontal. Since the last step has to be horizontal, it means our total path has to be an even number of steps. In other words, once we've reached the red squares, we have made the same amount of vertical and horizontal steps.
After each odd-numbered vertical step, we are an odd number of rows away from the starting point. After each even-numbered step, we are an even number of rows away. The same applies for horizontal steps.
In the end, we have taken the same number of steps both horizontally and vertically (i.e. either both are even or both are odd). We are 4 columns away from the starting point, so we must have taken an even number of horizontal steps. However, we are 5 rows away from the starting point, so we must have taken an odd number of vertical steps. This is impossible, so we can conclude that there is no such path through the maze.
answered 44 mins ago
jafejafe
21k458212
$endgroup$
$begingroup$
Very good; exactly what I had in mind. I'll wait a bit before accepting.
$endgroup$
– ZanyG
42 mins ago
add a comment |
$begingroup$
Since we must always turn 90 degrees, every odd-numbered step we take is always vertical and every even-numbered step is horizontal. Since the last step has to be horizontal, it means our total path has to be an even number of steps. In other words, once we've reached the red squares, we have made the same amount of vertical and horizontal steps.
After each odd-numbered vertical step, we are an odd number of rows away from the starting point. After each even-numbered step, we are an even number of rows away. The same applies for horizontal steps.
In the end, we have taken the same number of steps both horizontally and vertically (i.e. either both are even or both are odd). We are 4 columns away from the starting point, so we must have taken an even number of horizontal steps. However, we are 5 rows away from the starting point, so we must have taken an odd number of vertical steps. This is impossible, so we can conclude that there is no such path through the maze.
answered 44 mins ago
jafejafe
21k458212
$endgroup$
Since we must always turn 90 degrees, every odd-numbered step we take is always vertical and every even-numbered step is horizontal. Since the last step has to be horizontal, it means our total path has to be an even number of steps. In other words, once we've reached the red squares, we have made the same amount of vertical and horizontal steps.
After each odd-numbered vertical step, we are an odd number of rows away from the starting point. After each even-numbered step, we are an even number of rows away. The same applies for horizontal steps.
In the end, we have taken the same number of steps both horizontally and vertically (i.e. either both are even or both are odd). We are 4 columns away from the starting point, so we must have taken an even number of horizontal steps. However, we are 5 rows away from the starting point, so we must have taken an odd number of vertical steps. This is impossible, so we can conclude that there is no such path through the maze.
answered 44 mins ago
jafejafe
21k458212
answered 44 mins ago
jafejafe
21k458212
answered 44 mins ago
jafejafe
21k458212
answered 44 mins ago
jafejafe
21k458212
21k458212
$begingroup$
Very good; exactly what I had in mind. I'll wait a bit before accepting.
$endgroup$
– ZanyG
42 mins ago
add a comment |
$begingroup$
Very good; exactly what I had in mind. I'll wait a bit before accepting.
$endgroup$
– ZanyG
42 mins ago
$begingroup$
Very good; exactly what I had in mind. I'll wait a bit before accepting.
$endgroup$
– ZanyG
42 mins ago
$begingroup$
Very good; exactly what I had in mind. I'll wait a bit before accepting.
$endgroup$
– ZanyG
42 mins ago
add a comment |
$begingroup$
The path through the maze is:
non-existent.
Some notes about this -
The design of the maze is such that you'll basically be turning after following any line.
The missing segment is largely irrelevant.
Each step north, including the first, requires the next step to be east or west. Likewise for any step south.
You have to travel a net distance north of 5 steps.
After 1 step north + 1 step east/west, you're an ODD number of steps east or west of the starting position.
After two steps north + 1 east/west, you'll be an EVEN number of steps east or west of the start.
...
On a turn that leaves you 5 steps north, no matter how you get there, you'll be an even number of steps from the origin and about to have to turn east or west. The end state would require you to be an odd (3) number of steps west, so you will never be able to exit there.
answered 42 mins ago
Rubio♦Rubio
28.8k565178
$endgroup$
add a comment |
$begingroup$
The path through the maze is:
non-existent.
Some notes about this -
The design of the maze is such that you'll basically be turning after following any line.
The missing segment is largely irrelevant.
Each step north, including the first, requires the next step to be east or west. Likewise for any step south.
You have to travel a net distance north of 5 steps.
After 1 step north + 1 step east/west, you're an ODD number of steps east or west of the starting position.
After two steps north + 1 east/west, you'll be an EVEN number of steps east or west of the start.
...
On a turn that leaves you 5 steps north, no matter how you get there, you'll be an even number of steps from the origin and about to have to turn east or west. The end state would require you to be an odd (3) number of steps west, so you will never be able to exit there.
answered 42 mins ago
Rubio♦Rubio
28.8k565178
$endgroup$
add a comment |
$begingroup$
The path through the maze is:
non-existent.
Some notes about this -
The design of the maze is such that you'll basically be turning after following any line.
The missing segment is largely irrelevant.
Each step north, including the first, requires the next step to be east or west. Likewise for any step south.
You have to travel a net distance north of 5 steps.
After 1 step north + 1 step east/west, you're an ODD number of steps east or west of the starting position.
After two steps north + 1 east/west, you'll be an EVEN number of steps east or west of the start.
...
On a turn that leaves you 5 steps north, no matter how you get there, you'll be an even number of steps from the origin and about to have to turn east or west. The end state would require you to be an odd (3) number of steps west, so you will never be able to exit there.
answered 42 mins ago
Rubio♦Rubio
28.8k565178
$endgroup$
The path through the maze is:
non-existent.
Some notes about this -
The design of the maze is such that you'll basically be turning after following any line.
The missing segment is largely irrelevant.
Each step north, including the first, requires the next step to be east or west. Likewise for any step south.
You have to travel a net distance north of 5 steps.
After 1 step north + 1 step east/west, you're an ODD number of steps east or west of the starting position.
After two steps north + 1 east/west, you'll be an EVEN number of steps east or west of the start.
...
On a turn that leaves you 5 steps north, no matter how you get there, you'll be an even number of steps from the origin and about to have to turn east or west. The end state would require you to be an odd (3) number of steps west, so you will never be able to exit there.
answered 42 mins ago
Rubio♦Rubio
28.8k565178
answered 42 mins ago
Rubio♦Rubio
28.8k565178
answered 42 mins ago
Rubio♦Rubio
28.8k565178
answered 42 mins ago
Rubio♦Rubio
28.8k565178
28.8k565178
add a comment |
add a comment |
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