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Concatenating two int[]

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Concatenating two int[]


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6















There are easy solutions for concatenating two String[] or Integer[] in java by Streams. Since int[] is frequently used. Is there any straightforward way for concatenating two int[]?



Here is my thought:



int[] c = {1, 34};

int[] d = {3, 1, 5};

Integer[] cc = IntStream.of(c).boxed().toArray(Integer[]::new);

Integer[] dd = Arrays.stream(d).boxed().toArray(Integer[]::new);

int[] m = Stream.concat(Stream.of(cc), Stream.of(dd)).mapToInt(Integer::intValue).toArray();

System.out.println(Arrays.toString(m));



>>

[1, 34, 3, 1, 5]


It works, but it actually converts int[] to Integer[], then converts Integer[] back to int[] again.






java arrays lambda java-8 java-stream







share|improve this question





























    6















    There are easy solutions for concatenating two String[] or Integer[] in java by Streams. Since int[] is frequently used. Is there any straightforward way for concatenating two int[]?



    Here is my thought:



    int[] c = {1, 34};
    
int[] d = {3, 1, 5};
    
Integer[] cc = IntStream.of(c).boxed().toArray(Integer[]::new);
    
Integer[] dd = Arrays.stream(d).boxed().toArray(Integer[]::new);
    
int[] m = Stream.concat(Stream.of(cc), Stream.of(dd)).mapToInt(Integer::intValue).toArray();
    
System.out.println(Arrays.toString(m));
    

    
>>
    
[1, 34, 3, 1, 5]


    It works, but it actually converts int[] to Integer[], then converts Integer[] back to int[] again.






    java arrays lambda java-8 java-stream







    share|improve this question



























      6












      6








      6








      There are easy solutions for concatenating two String[] or Integer[] in java by Streams. Since int[] is frequently used. Is there any straightforward way for concatenating two int[]?



      Here is my thought:



      int[] c = {1, 34};
      
int[] d = {3, 1, 5};
      
Integer[] cc = IntStream.of(c).boxed().toArray(Integer[]::new);
      
Integer[] dd = Arrays.stream(d).boxed().toArray(Integer[]::new);
      
int[] m = Stream.concat(Stream.of(cc), Stream.of(dd)).mapToInt(Integer::intValue).toArray();
      
System.out.println(Arrays.toString(m));
      

      
>>
      
[1, 34, 3, 1, 5]


      It works, but it actually converts int[] to Integer[], then converts Integer[] back to int[] again.






      java arrays lambda java-8 java-stream







      share|improve this question
















      There are easy solutions for concatenating two String[] or Integer[] in java by Streams. Since int[] is frequently used. Is there any straightforward way for concatenating two int[]?



      Here is my thought:



      int[] c = {1, 34};
      
int[] d = {3, 1, 5};
      
Integer[] cc = IntStream.of(c).boxed().toArray(Integer[]::new);
      
Integer[] dd = Arrays.stream(d).boxed().toArray(Integer[]::new);
      
int[] m = Stream.concat(Stream.of(cc), Stream.of(dd)).mapToInt(Integer::intValue).toArray();
      
System.out.println(Arrays.toString(m));
      

      
>>
      
[1, 34, 3, 1, 5]


      It works, but it actually converts int[] to Integer[], then converts Integer[] back to int[] again.






      java arrays lambda java-8 java-stream




      java arrays lambda java-8 java-stream






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 2 hours ago









      nullpointer

      42.9k10101196




      42.9k10101196










      asked 3 hours ago









      Simon ZhangSimon Zhang

      343




      343
























          2 Answers
          2






          active

          oldest

          votes


















          5














          You can use IntStream.concat in concert with Arrays.stream to get this thing done without any auto-boxing or unboxing. Here's how it looks.



          int[] result = IntStream.concat(Arrays.stream(c), Arrays.stream(d)).toArray();


          Note that Arrays.stream(c) returns an IntStream, which is then concatenated with the other IntStream before collected into an array.



          Here's the output.




          [1, 34, 3, 1, 5]







          share|improve this answer

































            5














            You can simply concatenate primitive(int) streams as:



            int[] m = IntStream.concat(IntStream.of(c), IntStream.of(d)).toArray();





            share|improve this answer
























            • Just reads better in my opinion, though notably, the IntStream.of under the hood makes use of the Arrays.stream itself.

              – nullpointer
              2 hours ago













            Your Answer






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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            5














            You can use IntStream.concat in concert with Arrays.stream to get this thing done without any auto-boxing or unboxing. Here's how it looks.



            int[] result = IntStream.concat(Arrays.stream(c), Arrays.stream(d)).toArray();


            Note that Arrays.stream(c) returns an IntStream, which is then concatenated with the other IntStream before collected into an array.



            Here's the output.




            [1, 34, 3, 1, 5]







            share|improve this answer






























              5














              You can use IntStream.concat in concert with Arrays.stream to get this thing done without any auto-boxing or unboxing. Here's how it looks.



              int[] result = IntStream.concat(Arrays.stream(c), Arrays.stream(d)).toArray();


              Note that Arrays.stream(c) returns an IntStream, which is then concatenated with the other IntStream before collected into an array.



              Here's the output.




              [1, 34, 3, 1, 5]







              share|improve this answer




























                5












                5








                5







                You can use IntStream.concat in concert with Arrays.stream to get this thing done without any auto-boxing or unboxing. Here's how it looks.



                int[] result = IntStream.concat(Arrays.stream(c), Arrays.stream(d)).toArray();


                Note that Arrays.stream(c) returns an IntStream, which is then concatenated with the other IntStream before collected into an array.



                Here's the output.




                [1, 34, 3, 1, 5]







                share|improve this answer















                You can use IntStream.concat in concert with Arrays.stream to get this thing done without any auto-boxing or unboxing. Here's how it looks.



                int[] result = IntStream.concat(Arrays.stream(c), Arrays.stream(d)).toArray();


                Note that Arrays.stream(c) returns an IntStream, which is then concatenated with the other IntStream before collected into an array.



                Here's the output.




                [1, 34, 3, 1, 5]








                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 2 hours ago

























                answered 3 hours ago









                Ravindra RanwalaRavindra Ranwala

                10.1k31937




                10.1k31937

























                    5














                    You can simply concatenate primitive(int) streams as:



                    int[] m = IntStream.concat(IntStream.of(c), IntStream.of(d)).toArray();





                    share|improve this answer
























                    • Just reads better in my opinion, though notably, the IntStream.of under the hood makes use of the Arrays.stream itself.

                      – nullpointer
                      2 hours ago


















                    5














                    You can simply concatenate primitive(int) streams as:



                    int[] m = IntStream.concat(IntStream.of(c), IntStream.of(d)).toArray();





                    share|improve this answer
























                    • Just reads better in my opinion, though notably, the IntStream.of under the hood makes use of the Arrays.stream itself.

                      – nullpointer
                      2 hours ago
















                    5












                    5








                    5







                    You can simply concatenate primitive(int) streams as:



                    int[] m = IntStream.concat(IntStream.of(c), IntStream.of(d)).toArray();





                    share|improve this answer













                    You can simply concatenate primitive(int) streams as:



                    int[] m = IntStream.concat(IntStream.of(c), IntStream.of(d)).toArray();






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 2 hours ago









                    nullpointernullpointer

                    42.9k10101196




                    42.9k10101196













                    • Just reads better in my opinion, though notably, the IntStream.of under the hood makes use of the Arrays.stream itself.

                      – nullpointer
                      2 hours ago





















                    • Just reads better in my opinion, though notably, the IntStream.of under the hood makes use of the Arrays.stream itself.

                      – nullpointer
                      2 hours ago



















                    Just reads better in my opinion, though notably, the IntStream.of under the hood makes use of the Arrays.stream itself.

                    – nullpointer
                    2 hours ago







                    Just reads better in my opinion, though notably, the IntStream.of under the hood makes use of the Arrays.stream itself.

                    – nullpointer
                    2 hours ago




















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