my cron command doesn’t workWhy doesn't this script output to a text file when run from cron?Ubuntu 12.04...
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my cron command doesn’t work
Why doesn't this script output to a text file when run from cron?Ubuntu 12.04 cron not executingWhy won't cron run my sh script?How to execute livestreamer command with cron?Python 'Import pyodbc' does not work in a cron taskWhy doesn't my cron work?Cron does literally nothingCron jobs got executed, but it does not show any results at destination databaseCannot run python script with cronScript in cron not working
The commands that runs by source doesn’t work.
crontab -e
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
Content of cron file is 1.
command-line cron
edited 39 mins ago
dessert
24.1k670104
asked 2 hours ago
ahmadahmad
8010
add a comment |
The commands that runs by source doesn’t work.
crontab -e
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
Content of cron file is 1.
command-line cron
edited 39 mins ago
dessert
24.1k670104
asked 2 hours ago
ahmadahmad
8010
add a comment |
The commands that runs by source doesn’t work.
crontab -e
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
Content of cron file is 1.
command-line cron
edited 39 mins ago
dessert
24.1k670104
asked 2 hours ago
ahmadahmad
8010
The commands that runs by source doesn’t work.
crontab -e
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
Content of cron file is 1.
command-line cron
command-line cron
edited 39 mins ago
dessert
24.1k670104
asked 2 hours ago
ahmadahmad
8010
edited 39 mins ago
dessert
24.1k670104
asked 2 hours ago
ahmadahmad
8010
edited 39 mins ago
dessert
24.1k670104
edited 39 mins ago
dessert
24.1k670104
edited 39 mins ago
dessert
24.1k670104
24.1k670104
asked 2 hours ago
ahmadahmad
8010
asked 2 hours ago
ahmadahmad
8010
asked 2 hours ago
ahmadahmad
8010
8010
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
source is a bash-ism (or zsh-ism for that matter) whereas cron uses sh (dash) by default as the shell of choice.
So you need to use . instead of source to remain POSIX:
. "$HOME"/.zshrc
Or you can change the shell to any shell you want by using the SHELL variable of crontab e.g.:
SHELL=/usr/bin/zsh
You need to put this near the top of crontab, before any command entry.
Following your example:
SHELL=/usr/bin/zsh
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
And now you can stick with your original source approach.
This is the recommended approach for your case as you're source-ing .zshrc, presumably you have zsh specific declarations in there which won't work in sh.
If you don't want to set the SHELL variable, you can run the whole command as an argument to zsh -c, but this incurs careful quoting.
A safer approach would be to put the commands in a script, and run that as an executable with #!/usr/bin/env zsh shebang or as an argument to zsh (without making it executable).
As a side note, always quote your variable expansions unless you intentionally want to have word splitting and pathname expansion on them.
answered 2 hours ago
heemaylheemayl
67.1k9142214
I'd normally agree with sticking to/bin/sh- but given the OP is trying to source.zshrcthey may well need to set the shell tozsh
– steeldriver
1 hour ago
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
1 hour ago
@steeldriver Fair call. Edited.
– heemayl
1 hour ago
@ahmad Check my edits.
– heemayl
1 hour ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
1 hour ago
|
show 4 more comments
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votes
source is a bash-ism (or zsh-ism for that matter) whereas cron uses sh (dash) by default as the shell of choice.
So you need to use . instead of source to remain POSIX:
. "$HOME"/.zshrc
Or you can change the shell to any shell you want by using the SHELL variable of crontab e.g.:
SHELL=/usr/bin/zsh
You need to put this near the top of crontab, before any command entry.
Following your example:
SHELL=/usr/bin/zsh
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
And now you can stick with your original source approach.
This is the recommended approach for your case as you're source-ing .zshrc, presumably you have zsh specific declarations in there which won't work in sh.
If you don't want to set the SHELL variable, you can run the whole command as an argument to zsh -c, but this incurs careful quoting.
A safer approach would be to put the commands in a script, and run that as an executable with #!/usr/bin/env zsh shebang or as an argument to zsh (without making it executable).
As a side note, always quote your variable expansions unless you intentionally want to have word splitting and pathname expansion on them.
answered 2 hours ago
heemaylheemayl
67.1k9142214
I'd normally agree with sticking to/bin/sh- but given the OP is trying to source.zshrcthey may well need to set the shell tozsh
– steeldriver
1 hour ago
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
1 hour ago
@steeldriver Fair call. Edited.
– heemayl
1 hour ago
@ahmad Check my edits.
– heemayl
1 hour ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
1 hour ago
|
show 4 more comments
source is a bash-ism (or zsh-ism for that matter) whereas cron uses sh (dash) by default as the shell of choice.
So you need to use . instead of source to remain POSIX:
. "$HOME"/.zshrc
Or you can change the shell to any shell you want by using the SHELL variable of crontab e.g.:
SHELL=/usr/bin/zsh
You need to put this near the top of crontab, before any command entry.
Following your example:
SHELL=/usr/bin/zsh
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
And now you can stick with your original source approach.
This is the recommended approach for your case as you're source-ing .zshrc, presumably you have zsh specific declarations in there which won't work in sh.
If you don't want to set the SHELL variable, you can run the whole command as an argument to zsh -c, but this incurs careful quoting.
A safer approach would be to put the commands in a script, and run that as an executable with #!/usr/bin/env zsh shebang or as an argument to zsh (without making it executable).
As a side note, always quote your variable expansions unless you intentionally want to have word splitting and pathname expansion on them.
answered 2 hours ago
heemaylheemayl
67.1k9142214
I'd normally agree with sticking to/bin/sh- but given the OP is trying to source.zshrcthey may well need to set the shell tozsh
– steeldriver
1 hour ago
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
1 hour ago
@steeldriver Fair call. Edited.
– heemayl
1 hour ago
@ahmad Check my edits.
– heemayl
1 hour ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
1 hour ago
|
show 4 more comments
source is a bash-ism (or zsh-ism for that matter) whereas cron uses sh (dash) by default as the shell of choice.
So you need to use . instead of source to remain POSIX:
. "$HOME"/.zshrc
Or you can change the shell to any shell you want by using the SHELL variable of crontab e.g.:
SHELL=/usr/bin/zsh
You need to put this near the top of crontab, before any command entry.
Following your example:
SHELL=/usr/bin/zsh
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
And now you can stick with your original source approach.
This is the recommended approach for your case as you're source-ing .zshrc, presumably you have zsh specific declarations in there which won't work in sh.
If you don't want to set the SHELL variable, you can run the whole command as an argument to zsh -c, but this incurs careful quoting.
A safer approach would be to put the commands in a script, and run that as an executable with #!/usr/bin/env zsh shebang or as an argument to zsh (without making it executable).
As a side note, always quote your variable expansions unless you intentionally want to have word splitting and pathname expansion on them.
answered 2 hours ago
heemaylheemayl
67.1k9142214
source is a bash-ism (or zsh-ism for that matter) whereas cron uses sh (dash) by default as the shell of choice.
So you need to use . instead of source to remain POSIX:
. "$HOME"/.zshrc
Or you can change the shell to any shell you want by using the SHELL variable of crontab e.g.:
SHELL=/usr/bin/zsh
You need to put this near the top of crontab, before any command entry.
Following your example:
SHELL=/usr/bin/zsh
*/1 * * * * echo "1" > $HOME/cron && source $HOME/.zshrc && echo "2" >> $HOME/cron2 && source /home/alux/gitHub/rememberMe/.venv/bin/activate && echo "3" >> $HOME/cron && python /home/alux/gitHub/rememberMe/rememberMe/manage.py runcrons > /home/alux/gitHub/rememberMe/rememberMe/cronjobs.log && echo "4" >> $HOME/cron
And now you can stick with your original source approach.
This is the recommended approach for your case as you're source-ing .zshrc, presumably you have zsh specific declarations in there which won't work in sh.
If you don't want to set the SHELL variable, you can run the whole command as an argument to zsh -c, but this incurs careful quoting.
A safer approach would be to put the commands in a script, and run that as an executable with #!/usr/bin/env zsh shebang or as an argument to zsh (without making it executable).
As a side note, always quote your variable expansions unless you intentionally want to have word splitting and pathname expansion on them.
answered 2 hours ago
heemaylheemayl
67.1k9142214
edited 1 hour ago
answered 2 hours ago
heemaylheemayl
67.1k9142214
answered 2 hours ago
heemaylheemayl
67.1k9142214
answered 2 hours ago
heemaylheemayl
67.1k9142214
67.1k9142214
I'd normally agree with sticking to/bin/sh- but given the OP is trying to source.zshrcthey may well need to set the shell tozsh
– steeldriver
1 hour ago
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
1 hour ago
@steeldriver Fair call. Edited.
– heemayl
1 hour ago
@ahmad Check my edits.
– heemayl
1 hour ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
1 hour ago
|
show 4 more comments
I'd normally agree with sticking to/bin/sh- but given the OP is trying to source.zshrcthey may well need to set the shell tozsh
– steeldriver
1 hour ago
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
1 hour ago
@steeldriver Fair call. Edited.
– heemayl
1 hour ago
@ahmad Check my edits.
– heemayl
1 hour ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
1 hour ago
I'd normally agree with sticking to
/bin/sh - but given the OP is trying to source .zshrc they may well need to set the shell to zsh– steeldriver
1 hour ago
I'd normally agree with sticking to
/bin/sh - but given the OP is trying to source .zshrc they may well need to set the shell to zsh– steeldriver
1 hour ago
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
1 hour ago
I changed it by but it dosent work yet :*/1 * * * * echo "1" > $HOME/cron && . "$HOME"/.bashrc && echo "2" >> $HOME/cron2
– ahmad
1 hour ago
@steeldriver Fair call. Edited.
– heemayl
1 hour ago
@steeldriver Fair call. Edited.
– heemayl
1 hour ago
@ahmad Check my edits.
– heemayl
1 hour ago
@ahmad Check my edits.
– heemayl
1 hour ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
1 hour ago
@steeldriver I Changed it to :*/1 * * * * SHELL=/usr/bin/zsh && echo "1" > $HOME/cron && source "$HOME"/.bashrc && echo "2" >> $HOME/cron2 , But it Dosent work yet :(
– ahmad
1 hour ago
|
show 4 more comments
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