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How to find the average rate of a function?


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2












$begingroup$


enter image description here



I have these two problems.
For the first one I know that



$f(x) = 50000+25x$ If I wanted to find the average cost, how would I do that? I'm confused about the equation I would need to set up.



For the second question, I was thinking that the average is just the average of 62 and 68, is this correct?






algebra-precalculus







share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
    $endgroup$
    – saulspatz
    5 hours ago










  • $begingroup$
    no can you please explain what the definition of average cost is?
    $endgroup$
    – user130306
    3 hours ago










  • $begingroup$
    Thomas Fjærvik's answer explains it very well.
    $endgroup$
    – saulspatz
    3 hours ago
















2












$begingroup$


enter image description here



I have these two problems.
For the first one I know that



$f(x) = 50000+25x$ If I wanted to find the average cost, how would I do that? I'm confused about the equation I would need to set up.



For the second question, I was thinking that the average is just the average of 62 and 68, is this correct?






algebra-precalculus







share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
    $endgroup$
    – saulspatz
    5 hours ago










  • $begingroup$
    no can you please explain what the definition of average cost is?
    $endgroup$
    – user130306
    3 hours ago










  • $begingroup$
    Thomas Fjærvik's answer explains it very well.
    $endgroup$
    – saulspatz
    3 hours ago














2












2








2





$begingroup$


enter image description here



I have these two problems.
For the first one I know that



$f(x) = 50000+25x$ If I wanted to find the average cost, how would I do that? I'm confused about the equation I would need to set up.



For the second question, I was thinking that the average is just the average of 62 and 68, is this correct?






algebra-precalculus







share|cite|improve this question









$endgroup$




enter image description here



I have these two problems.
For the first one I know that



$f(x) = 50000+25x$ If I wanted to find the average cost, how would I do that? I'm confused about the equation I would need to set up.



For the second question, I was thinking that the average is just the average of 62 and 68, is this correct?






algebra-precalculus




algebra-precalculus






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 5 hours ago









user130306user130306

45618




45618








  • 1




    $begingroup$
    For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
    $endgroup$
    – saulspatz
    5 hours ago










  • $begingroup$
    no can you please explain what the definition of average cost is?
    $endgroup$
    – user130306
    3 hours ago










  • $begingroup$
    Thomas Fjærvik's answer explains it very well.
    $endgroup$
    – saulspatz
    3 hours ago














  • 1




    $begingroup$
    For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
    $endgroup$
    – saulspatz
    5 hours ago










  • $begingroup$
    no can you please explain what the definition of average cost is?
    $endgroup$
    – user130306
    3 hours ago










  • $begingroup$
    Thomas Fjærvik's answer explains it very well.
    $endgroup$
    – saulspatz
    3 hours ago








1




1




$begingroup$
For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
$endgroup$
– saulspatz
5 hours ago




$begingroup$
For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
$endgroup$
– saulspatz
5 hours ago












$begingroup$
no can you please explain what the definition of average cost is?
$endgroup$
– user130306
3 hours ago




$begingroup$
no can you please explain what the definition of average cost is?
$endgroup$
– user130306
3 hours ago












$begingroup$
Thomas Fjærvik's answer explains it very well.
$endgroup$
– saulspatz
3 hours ago




$begingroup$
Thomas Fjærvik's answer explains it very well.
$endgroup$
– saulspatz
3 hours ago










2 Answers
2






active

oldest

votes


















3












$begingroup$

Think about it this way. The average cost is the total cost of the calculators divided by the number of calculators. Total cost is $50000 + 25x$ and number of calculators is $x$. Setting this average equal to $35$ gives you the equation given by mfl






share|cite|improve this answer








New contributor




Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    ohh! that makes sense, thank you!
    $endgroup$
    – user130306
    3 hours ago



















1












$begingroup$

First question



You have to solve $50000+25x=35x.$



Second question



$s=62cdot t_1$ and $s=68 cdot t_2.$ Now, $v=frac{2s}{t_1+t_2}.$






share|cite|improve this answer









$endgroup$













  • $begingroup$
    can you please explain why i have to use that formula for the second equation?
    $endgroup$
    – user130306
    3 hours ago






  • 3




    $begingroup$
    $s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
    $endgroup$
    – Thomas Fjærvik
    3 hours ago











Your Answer





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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









3












$begingroup$

Think about it this way. The average cost is the total cost of the calculators divided by the number of calculators. Total cost is $50000 + 25x$ and number of calculators is $x$. Setting this average equal to $35$ gives you the equation given by mfl






share|cite|improve this answer








New contributor




Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    ohh! that makes sense, thank you!
    $endgroup$
    – user130306
    3 hours ago
















3












$begingroup$

Think about it this way. The average cost is the total cost of the calculators divided by the number of calculators. Total cost is $50000 + 25x$ and number of calculators is $x$. Setting this average equal to $35$ gives you the equation given by mfl






share|cite|improve this answer








New contributor




Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    ohh! that makes sense, thank you!
    $endgroup$
    – user130306
    3 hours ago














3












3








3





$begingroup$

Think about it this way. The average cost is the total cost of the calculators divided by the number of calculators. Total cost is $50000 + 25x$ and number of calculators is $x$. Setting this average equal to $35$ gives you the equation given by mfl






share|cite|improve this answer








New contributor




Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$



Think about it this way. The average cost is the total cost of the calculators divided by the number of calculators. Total cost is $50000 + 25x$ and number of calculators is $x$. Setting this average equal to $35$ gives you the equation given by mfl







share|cite|improve this answer








New contributor




Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this answer



share|cite|improve this answer






New contributor




Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









answered 5 hours ago









Thomas FjærvikThomas Fjærvik

1386




1386




New contributor




Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    ohh! that makes sense, thank you!
    $endgroup$
    – user130306
    3 hours ago


















  • $begingroup$
    ohh! that makes sense, thank you!
    $endgroup$
    – user130306
    3 hours ago
















$begingroup$
ohh! that makes sense, thank you!
$endgroup$
– user130306
3 hours ago




$begingroup$
ohh! that makes sense, thank you!
$endgroup$
– user130306
3 hours ago











1












$begingroup$

First question



You have to solve $50000+25x=35x.$



Second question



$s=62cdot t_1$ and $s=68 cdot t_2.$ Now, $v=frac{2s}{t_1+t_2}.$






share|cite|improve this answer









$endgroup$













  • $begingroup$
    can you please explain why i have to use that formula for the second equation?
    $endgroup$
    – user130306
    3 hours ago






  • 3




    $begingroup$
    $s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
    $endgroup$
    – Thomas Fjærvik
    3 hours ago
















1












$begingroup$

First question



You have to solve $50000+25x=35x.$



Second question



$s=62cdot t_1$ and $s=68 cdot t_2.$ Now, $v=frac{2s}{t_1+t_2}.$






share|cite|improve this answer









$endgroup$













  • $begingroup$
    can you please explain why i have to use that formula for the second equation?
    $endgroup$
    – user130306
    3 hours ago






  • 3




    $begingroup$
    $s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
    $endgroup$
    – Thomas Fjærvik
    3 hours ago














1












1








1





$begingroup$

First question



You have to solve $50000+25x=35x.$



Second question



$s=62cdot t_1$ and $s=68 cdot t_2.$ Now, $v=frac{2s}{t_1+t_2}.$






share|cite|improve this answer









$endgroup$



First question



You have to solve $50000+25x=35x.$



Second question



$s=62cdot t_1$ and $s=68 cdot t_2.$ Now, $v=frac{2s}{t_1+t_2}.$







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered 5 hours ago









mflmfl

26.7k12142




26.7k12142












  • $begingroup$
    can you please explain why i have to use that formula for the second equation?
    $endgroup$
    – user130306
    3 hours ago






  • 3




    $begingroup$
    $s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
    $endgroup$
    – Thomas Fjærvik
    3 hours ago


















  • $begingroup$
    can you please explain why i have to use that formula for the second equation?
    $endgroup$
    – user130306
    3 hours ago






  • 3




    $begingroup$
    $s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
    $endgroup$
    – Thomas Fjærvik
    3 hours ago
















$begingroup$
can you please explain why i have to use that formula for the second equation?
$endgroup$
– user130306
3 hours ago




$begingroup$
can you please explain why i have to use that formula for the second equation?
$endgroup$
– user130306
3 hours ago




3




3




$begingroup$
$s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
$endgroup$
– Thomas Fjærvik
3 hours ago




$begingroup$
$s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
$endgroup$
– Thomas Fjærvik
3 hours ago


















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