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How to find the average rate of a function?
How to normalize a range of values taking the difference into considerationCalculating Average Rate of ReturnHow does one create a step function?Average mileage problemFind the growth rate for $y=4^{x +1}$Thinking Problem Involving Average Rate of ChangeDetermine two changing variables only knowing the resultMortgage finance principal with two loans - find optimum & average rateHow to work out average speed in problem solving question?Adding compounding rent to a rent per employee calculation while accounting for free months rent?
$begingroup$
I have these two problems.
For the first one I know that
$f(x) = 50000+25x$ If I wanted to find the average cost, how would I do that? I'm confused about the equation I would need to set up.
For the second question, I was thinking that the average is just the average of 62 and 68, is this correct?
algebra-precalculus
asked 5 hours ago
user130306user130306
45618
$endgroup$
add a comment |
$begingroup$
I have these two problems.
For the first one I know that
$f(x) = 50000+25x$ If I wanted to find the average cost, how would I do that? I'm confused about the equation I would need to set up.
For the second question, I was thinking that the average is just the average of 62 and 68, is this correct?
algebra-precalculus
asked 5 hours ago
user130306user130306
45618
$endgroup$
1
$begingroup$
For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
$endgroup$
– saulspatz
5 hours ago
$begingroup$
no can you please explain what the definition of average cost is?
$endgroup$
– user130306
3 hours ago
$begingroup$
Thomas Fjærvik's answer explains it very well.
$endgroup$
– saulspatz
3 hours ago
add a comment |
$begingroup$
I have these two problems.
For the first one I know that
$f(x) = 50000+25x$ If I wanted to find the average cost, how would I do that? I'm confused about the equation I would need to set up.
For the second question, I was thinking that the average is just the average of 62 and 68, is this correct?
algebra-precalculus
asked 5 hours ago
user130306user130306
45618
$endgroup$
I have these two problems.
For the first one I know that
$f(x) = 50000+25x$ If I wanted to find the average cost, how would I do that? I'm confused about the equation I would need to set up.
For the second question, I was thinking that the average is just the average of 62 and 68, is this correct?
algebra-precalculus
algebra-precalculus
asked 5 hours ago
user130306user130306
45618
asked 5 hours ago
user130306user130306
45618
asked 5 hours ago
user130306user130306
45618
asked 5 hours ago
user130306user130306
45618
asked 5 hours ago
user130306user130306
45618
45618
1
$begingroup$
For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
$endgroup$
– saulspatz
5 hours ago
$begingroup$
no can you please explain what the definition of average cost is?
$endgroup$
– user130306
3 hours ago
$begingroup$
Thomas Fjærvik's answer explains it very well.
$endgroup$
– saulspatz
3 hours ago
add a comment |
1
$begingroup$
For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
$endgroup$
– saulspatz
5 hours ago
$begingroup$
no can you please explain what the definition of average cost is?
$endgroup$
– user130306
3 hours ago
$begingroup$
Thomas Fjærvik's answer explains it very well.
$endgroup$
– saulspatz
3 hours ago
1
1
$begingroup$
For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
$endgroup$
– saulspatz
5 hours ago
$begingroup$
For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
$endgroup$
– saulspatz
5 hours ago
$begingroup$
no can you please explain what the definition of average cost is?
$endgroup$
– user130306
3 hours ago
$begingroup$
no can you please explain what the definition of average cost is?
$endgroup$
– user130306
3 hours ago
$begingroup$
Thomas Fjærvik's answer explains it very well.
$endgroup$
– saulspatz
3 hours ago
$begingroup$
Thomas Fjærvik's answer explains it very well.
$endgroup$
– saulspatz
3 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Think about it this way. The average cost is the total cost of the calculators divided by the number of calculators. Total cost is $50000 + 25x$ and number of calculators is $x$. Setting this average equal to $35$ gives you the equation given by mfl
answered 5 hours ago
Thomas FjærvikThomas Fjærvik
1386
New contributor
Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
ohh! that makes sense, thank you!
$endgroup$
– user130306
3 hours ago
add a comment |
$begingroup$
First question
You have to solve $50000+25x=35x.$
Second question
$s=62cdot t_1$ and $s=68 cdot t_2.$ Now, $v=frac{2s}{t_1+t_2}.$
answered 5 hours ago
mflmfl
26.7k12142
$endgroup$
$begingroup$
can you please explain why i have to use that formula for the second equation?
$endgroup$
– user130306
3 hours ago
3
$begingroup$
$s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
$endgroup$
– Thomas Fjærvik
3 hours ago
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Think about it this way. The average cost is the total cost of the calculators divided by the number of calculators. Total cost is $50000 + 25x$ and number of calculators is $x$. Setting this average equal to $35$ gives you the equation given by mfl
answered 5 hours ago
Thomas FjærvikThomas Fjærvik
1386
New contributor
Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
ohh! that makes sense, thank you!
$endgroup$
– user130306
3 hours ago
add a comment |
$begingroup$
Think about it this way. The average cost is the total cost of the calculators divided by the number of calculators. Total cost is $50000 + 25x$ and number of calculators is $x$. Setting this average equal to $35$ gives you the equation given by mfl
answered 5 hours ago
Thomas FjærvikThomas Fjærvik
1386
New contributor
Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
ohh! that makes sense, thank you!
$endgroup$
– user130306
3 hours ago
add a comment |
$begingroup$
Think about it this way. The average cost is the total cost of the calculators divided by the number of calculators. Total cost is $50000 + 25x$ and number of calculators is $x$. Setting this average equal to $35$ gives you the equation given by mfl
answered 5 hours ago
Thomas FjærvikThomas Fjærvik
1386
New contributor
Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Think about it this way. The average cost is the total cost of the calculators divided by the number of calculators. Total cost is $50000 + 25x$ and number of calculators is $x$. Setting this average equal to $35$ gives you the equation given by mfl
answered 5 hours ago
Thomas FjærvikThomas Fjærvik
1386
New contributor
Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 5 hours ago
Thomas FjærvikThomas Fjærvik
1386
New contributor
Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 5 hours ago
Thomas FjærvikThomas Fjærvik
1386
answered 5 hours ago
Thomas FjærvikThomas Fjærvik
1386
1386
New contributor
Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Thomas Fjærvik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
ohh! that makes sense, thank you!
$endgroup$
– user130306
3 hours ago
add a comment |
$begingroup$
ohh! that makes sense, thank you!
$endgroup$
– user130306
3 hours ago
$begingroup$
ohh! that makes sense, thank you!
$endgroup$
– user130306
3 hours ago
$begingroup$
ohh! that makes sense, thank you!
$endgroup$
– user130306
3 hours ago
add a comment |
$begingroup$
First question
You have to solve $50000+25x=35x.$
Second question
$s=62cdot t_1$ and $s=68 cdot t_2.$ Now, $v=frac{2s}{t_1+t_2}.$
answered 5 hours ago
mflmfl
26.7k12142
$endgroup$
$begingroup$
can you please explain why i have to use that formula for the second equation?
$endgroup$
– user130306
3 hours ago
3
$begingroup$
$s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
$endgroup$
– Thomas Fjærvik
3 hours ago
add a comment |
$begingroup$
First question
You have to solve $50000+25x=35x.$
Second question
$s=62cdot t_1$ and $s=68 cdot t_2.$ Now, $v=frac{2s}{t_1+t_2}.$
answered 5 hours ago
mflmfl
26.7k12142
$endgroup$
$begingroup$
can you please explain why i have to use that formula for the second equation?
$endgroup$
– user130306
3 hours ago
3
$begingroup$
$s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
$endgroup$
– Thomas Fjærvik
3 hours ago
add a comment |
$begingroup$
First question
You have to solve $50000+25x=35x.$
Second question
$s=62cdot t_1$ and $s=68 cdot t_2.$ Now, $v=frac{2s}{t_1+t_2}.$
answered 5 hours ago
mflmfl
26.7k12142
$endgroup$
First question
You have to solve $50000+25x=35x.$
Second question
$s=62cdot t_1$ and $s=68 cdot t_2.$ Now, $v=frac{2s}{t_1+t_2}.$
answered 5 hours ago
mflmfl
26.7k12142
answered 5 hours ago
mflmfl
26.7k12142
answered 5 hours ago
mflmfl
26.7k12142
answered 5 hours ago
mflmfl
26.7k12142
26.7k12142
$begingroup$
can you please explain why i have to use that formula for the second equation?
$endgroup$
– user130306
3 hours ago
3
$begingroup$
$s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
$endgroup$
– Thomas Fjærvik
3 hours ago
add a comment |
$begingroup$
can you please explain why i have to use that formula for the second equation?
$endgroup$
– user130306
3 hours ago
3
$begingroup$
$s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
$endgroup$
– Thomas Fjærvik
3 hours ago
$begingroup$
can you please explain why i have to use that formula for the second equation?
$endgroup$
– user130306
3 hours ago
$begingroup$
can you please explain why i have to use that formula for the second equation?
$endgroup$
– user130306
3 hours ago
3
3
$begingroup$
$s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
$endgroup$
– Thomas Fjærvik
3 hours ago
$begingroup$
$s$ represents the distance covered. One way it is covered by driving at $62$ mph in $t_1$ hours, the other way by driving at $68$ mph for $t_2$ hours. The average velocity is given by the total distance traveled divided by the total time spent driving.
$endgroup$
– Thomas Fjærvik
3 hours ago
add a comment |
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1
$begingroup$
For your first question, do you know the definition of average cost? For the second question, no that's not right. You spend more time traveling at the slower speed. Again, what is the definition of average speed?
$endgroup$
– saulspatz
5 hours ago
$begingroup$
no can you please explain what the definition of average cost is?
$endgroup$
– user130306
3 hours ago
$begingroup$
Thomas Fjærvik's answer explains it very well.
$endgroup$
– saulspatz
3 hours ago