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Fraction within another fraction

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Fraction within another fraction

Fraction with doubled lineCan't make a fractionFraction in bracketsProblem with fractionFraction Brackets sizeIncrease margin between tilde and line of fractionSubscript within a fractionFraction lines?Why fraction (with power) in fraction doesn't work?Shorten fraction line

1

Im using the code as shown below to write a step by step for a question but when i have a fraction in another fraction it becomes small and hard to read. i wish to make the faction inside the same size as the other and clear but not too crowded.

begin{align*}

    frac{sin(a+b)}{cos(a+b)}&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    &=frac{frac{sin a cos b}{cos a cos b} + frac{cos a sin b}{cos a cos b}}{frac{cos a cos b}{cos a cos b} - frac{sin a sin b}{cos a cos b}}

    \

    &=frac{frac{sin a}{cos a} + frac{sin b}{cos b}}{1 - frac{sin a sin b}{cos a cos b}}

    \

    &=frac{tan a +tan b }{1 - tan a tan b}

end{align*}

fractions

share|improve this question

asked 26 mins ago

Jettie BakerJettie Baker

254

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Add displaystyle before the small fraction, or (with amsmath), use dfrac.
  
  – Steven B. Segletes
  24 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  when i do that there ends up having a really small gap between the small fraction bottom and big fractions line and other small fraction top
  
  – Jettie Baker
  22 mins ago
  

  
  
  
  

add a comment | 

1

Im using the code as shown below to write a step by step for a question but when i have a fraction in another fraction it becomes small and hard to read. i wish to make the faction inside the same size as the other and clear but not too crowded.

begin{align*}

    frac{sin(a+b)}{cos(a+b)}&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    &=frac{frac{sin a cos b}{cos a cos b} + frac{cos a sin b}{cos a cos b}}{frac{cos a cos b}{cos a cos b} - frac{sin a sin b}{cos a cos b}}

    \

    &=frac{frac{sin a}{cos a} + frac{sin b}{cos b}}{1 - frac{sin a sin b}{cos a cos b}}

    \

    &=frac{tan a +tan b }{1 - tan a tan b}

end{align*}

fractions

share|improve this question

asked 26 mins ago

Jettie BakerJettie Baker

254

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Add displaystyle before the small fraction, or (with amsmath), use dfrac.
  
  – Steven B. Segletes
  24 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  when i do that there ends up having a really small gap between the small fraction bottom and big fractions line and other small fraction top
  
  – Jettie Baker
  22 mins ago
  

  
  
  
  

add a comment | 

Im using the code as shown below to write a step by step for a question but when i have a fraction in another fraction it becomes small and hard to read. i wish to make the faction inside the same size as the other and clear but not too crowded.

begin{align*}

    frac{sin(a+b)}{cos(a+b)}&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    &=frac{frac{sin a cos b}{cos a cos b} + frac{cos a sin b}{cos a cos b}}{frac{cos a cos b}{cos a cos b} - frac{sin a sin b}{cos a cos b}}

    \

    &=frac{frac{sin a}{cos a} + frac{sin b}{cos b}}{1 - frac{sin a sin b}{cos a cos b}}

    \

    &=frac{tan a +tan b }{1 - tan a tan b}

end{align*}

fractions

share|improve this question

asked 26 mins ago

Jettie BakerJettie Baker

254

begin{align*}

    frac{sin(a+b)}{cos(a+b)}&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    &=frac{frac{sin a cos b}{cos a cos b} + frac{cos a sin b}{cos a cos b}}{frac{cos a cos b}{cos a cos b} - frac{sin a sin b}{cos a cos b}}

    \

    &=frac{frac{sin a}{cos a} + frac{sin b}{cos b}}{1 - frac{sin a sin b}{cos a cos b}}

    \

    &=frac{tan a +tan b }{1 - tan a tan b}

end{align*}

share|improve this question

asked 26 mins ago

Jettie BakerJettie Baker

254

share|improve this question

asked 26 mins ago

Jettie BakerJettie Baker

254

asked 26 mins ago

Jettie BakerJettie Baker

254

asked 26 mins ago

Jettie BakerJettie Baker

254

2 Answers
2

active

oldest

votes

2

To remedy the small (textstyle) equations, as I said in a comment, add displaystyle before the small fraction, or (with amsmath), use dfrac. However, that does not address the narrow vertical gap between really tall equations.

With a TABstack, the gap between equations can be easily specified. Here, because the equation(s) is/are unnumbered, and the height of each equation is different, I choose a alignShortstack instead of an alignCenterstack

documentclass{article}

usepackage{amsmath,tabstackengine}

TABstackMath

TABstackMathstyle{displaystyle}

begin{document}

[

setstackgap{S}{16pt}

alignShortstack{

    frac{sin(a+b)}{cos(a+b)}&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    &=frac{dfrac{sin a cos b}{cos a cos b} + dfrac{cos a sin b}{cos a cos b}}{dfrac{cos a cos b}{cos a cos b} - dfrac{sin a sin b}{cos a cos b}}

    \

    &=frac{dfrac{sin a}{cos a} + dfrac{sin b}{cos b}}{1 - dfrac{sin a sin b}{cos a cos b}}

    \

    &=frac{tan a +tan b }{1 - tan a tan b}}

]

end{document}

share|improve this answer

answered 18 mins ago

Steven B. SegletesSteven B. Segletes

156k9202411

add a comment | 

1

with use of amsmath and manuals increased vertical distance between math equation's lines:

documentclass{article}

usepackage{amsmath}



begin{document}

    begin{align*}

frac{sin(a+b)}{cos(a+b)}

&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}               \

tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}      \[1ex]

&=frac{dfrac{sin a cos b}{cos a cos b} + dfrac{cos a sin b}{cos a cos b}}

       {dfrac{cos a cos b}{cos a cos b} - dfrac{sin a sin b}{cos a cos b}}\[1ex]

&=frac{dfrac{sin a}{cos a} + dfrac{sin b}{cos b}}

       {1 - dfrac{sin a sin b}{cos a cos b}}                                   \[1ex]

    &=frac{tan a +tan b }{1 - tan a tan b}

end{align*}

end{document}

share|improve this answer

answered 13 mins ago

ZarkoZarko

125k867164

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The fractions in the numerator appear too close to the fraction line compared to what's below the fraction line. This might be improved by adding mathstrut to each of the denominators in the numerator fractions. (But it will probably never look wonderful.)
  
  – barbara beeton
  23 secs ago
  

  
  
  
  

add a comment | 

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2

To remedy the small (textstyle) equations, as I said in a comment, add displaystyle before the small fraction, or (with amsmath), use dfrac. However, that does not address the narrow vertical gap between really tall equations.

With a TABstack, the gap between equations can be easily specified. Here, because the equation(s) is/are unnumbered, and the height of each equation is different, I choose a alignShortstack instead of an alignCenterstack

documentclass{article}

usepackage{amsmath,tabstackengine}

TABstackMath

TABstackMathstyle{displaystyle}

begin{document}

[

setstackgap{S}{16pt}

alignShortstack{

    frac{sin(a+b)}{cos(a+b)}&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    &=frac{dfrac{sin a cos b}{cos a cos b} + dfrac{cos a sin b}{cos a cos b}}{dfrac{cos a cos b}{cos a cos b} - dfrac{sin a sin b}{cos a cos b}}

    \

    &=frac{dfrac{sin a}{cos a} + dfrac{sin b}{cos b}}{1 - dfrac{sin a sin b}{cos a cos b}}

    \

    &=frac{tan a +tan b }{1 - tan a tan b}}

]

end{document}

share|improve this answer

answered 18 mins ago

Steven B. SegletesSteven B. Segletes

156k9202411

add a comment | 

2

To remedy the small (textstyle) equations, as I said in a comment, add displaystyle before the small fraction, or (with amsmath), use dfrac. However, that does not address the narrow vertical gap between really tall equations.

With a TABstack, the gap between equations can be easily specified. Here, because the equation(s) is/are unnumbered, and the height of each equation is different, I choose a alignShortstack instead of an alignCenterstack

documentclass{article}

usepackage{amsmath,tabstackengine}

TABstackMath

TABstackMathstyle{displaystyle}

begin{document}

[

setstackgap{S}{16pt}

alignShortstack{

    frac{sin(a+b)}{cos(a+b)}&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    &=frac{dfrac{sin a cos b}{cos a cos b} + dfrac{cos a sin b}{cos a cos b}}{dfrac{cos a cos b}{cos a cos b} - dfrac{sin a sin b}{cos a cos b}}

    \

    &=frac{dfrac{sin a}{cos a} + dfrac{sin b}{cos b}}{1 - dfrac{sin a sin b}{cos a cos b}}

    \

    &=frac{tan a +tan b }{1 - tan a tan b}}

]

end{document}

share|improve this answer

answered 18 mins ago

Steven B. SegletesSteven B. Segletes

156k9202411

add a comment | 

To remedy the small (textstyle) equations, as I said in a comment, add displaystyle before the small fraction, or (with amsmath), use dfrac. However, that does not address the narrow vertical gap between really tall equations.

With a TABstack, the gap between equations can be easily specified. Here, because the equation(s) is/are unnumbered, and the height of each equation is different, I choose a alignShortstack instead of an alignCenterstack

documentclass{article}

usepackage{amsmath,tabstackengine}

TABstackMath

TABstackMathstyle{displaystyle}

begin{document}

[

setstackgap{S}{16pt}

alignShortstack{

    frac{sin(a+b)}{cos(a+b)}&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    &=frac{dfrac{sin a cos b}{cos a cos b} + dfrac{cos a sin b}{cos a cos b}}{dfrac{cos a cos b}{cos a cos b} - dfrac{sin a sin b}{cos a cos b}}

    \

    &=frac{dfrac{sin a}{cos a} + dfrac{sin b}{cos b}}{1 - dfrac{sin a sin b}{cos a cos b}}

    \

    &=frac{tan a +tan b }{1 - tan a tan b}}

]

end{document}

share|improve this answer

answered 18 mins ago

Steven B. SegletesSteven B. Segletes

156k9202411

documentclass{article}

usepackage{amsmath,tabstackengine}

TABstackMath

TABstackMathstyle{displaystyle}

begin{document}

[

setstackgap{S}{16pt}

alignShortstack{

    frac{sin(a+b)}{cos(a+b)}&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}

    \

    &=frac{dfrac{sin a cos b}{cos a cos b} + dfrac{cos a sin b}{cos a cos b}}{dfrac{cos a cos b}{cos a cos b} - dfrac{sin a sin b}{cos a cos b}}

    \

    &=frac{dfrac{sin a}{cos a} + dfrac{sin b}{cos b}}{1 - dfrac{sin a sin b}{cos a cos b}}

    \

    &=frac{tan a +tan b }{1 - tan a tan b}}

]

end{document}

share|improve this answer

answered 18 mins ago

Steven B. SegletesSteven B. Segletes

156k9202411

answered 18 mins ago

Steven B. SegletesSteven B. Segletes

156k9202411

answered 18 mins ago

Steven B. SegletesSteven B. Segletes

156k9202411

1

with use of amsmath and manuals increased vertical distance between math equation's lines:

documentclass{article}

usepackage{amsmath}



begin{document}

    begin{align*}

frac{sin(a+b)}{cos(a+b)}

&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}               \

tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}      \[1ex]

&=frac{dfrac{sin a cos b}{cos a cos b} + dfrac{cos a sin b}{cos a cos b}}

       {dfrac{cos a cos b}{cos a cos b} - dfrac{sin a sin b}{cos a cos b}}\[1ex]

&=frac{dfrac{sin a}{cos a} + dfrac{sin b}{cos b}}

       {1 - dfrac{sin a sin b}{cos a cos b}}                                   \[1ex]

    &=frac{tan a +tan b }{1 - tan a tan b}

end{align*}

end{document}

share|improve this answer

answered 13 mins ago

ZarkoZarko

125k867164

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The fractions in the numerator appear too close to the fraction line compared to what's below the fraction line. This might be improved by adding mathstrut to each of the denominators in the numerator fractions. (But it will probably never look wonderful.)
  
  – barbara beeton
  23 secs ago
  

  
  
  
  

add a comment | 

1

with use of amsmath and manuals increased vertical distance between math equation's lines:

documentclass{article}

usepackage{amsmath}



begin{document}

    begin{align*}

frac{sin(a+b)}{cos(a+b)}

&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}               \

tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}      \[1ex]

&=frac{dfrac{sin a cos b}{cos a cos b} + dfrac{cos a sin b}{cos a cos b}}

       {dfrac{cos a cos b}{cos a cos b} - dfrac{sin a sin b}{cos a cos b}}\[1ex]

&=frac{dfrac{sin a}{cos a} + dfrac{sin b}{cos b}}

       {1 - dfrac{sin a sin b}{cos a cos b}}                                   \[1ex]

    &=frac{tan a +tan b }{1 - tan a tan b}

end{align*}

end{document}

share|improve this answer

answered 13 mins ago

ZarkoZarko

125k867164

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The fractions in the numerator appear too close to the fraction line compared to what's below the fraction line. This might be improved by adding mathstrut to each of the denominators in the numerator fractions. (But it will probably never look wonderful.)
  
  – barbara beeton
  23 secs ago
  

  
  
  
  

add a comment | 

with use of amsmath and manuals increased vertical distance between math equation's lines:

documentclass{article}

usepackage{amsmath}



begin{document}

    begin{align*}

frac{sin(a+b)}{cos(a+b)}

&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}               \

tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}      \[1ex]

&=frac{dfrac{sin a cos b}{cos a cos b} + dfrac{cos a sin b}{cos a cos b}}

       {dfrac{cos a cos b}{cos a cos b} - dfrac{sin a sin b}{cos a cos b}}\[1ex]

&=frac{dfrac{sin a}{cos a} + dfrac{sin b}{cos b}}

       {1 - dfrac{sin a sin b}{cos a cos b}}                                   \[1ex]

    &=frac{tan a +tan b }{1 - tan a tan b}

end{align*}

end{document}

share|improve this answer

answered 13 mins ago

ZarkoZarko

125k867164

documentclass{article}

usepackage{amsmath}



begin{document}

    begin{align*}

frac{sin(a+b)}{cos(a+b)}

&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}               \

tan(a+b)&=frac{sin a cos b + cos a sin b}{cos a cos b - sin a sin b}      \[1ex]

&=frac{dfrac{sin a cos b}{cos a cos b} + dfrac{cos a sin b}{cos a cos b}}

       {dfrac{cos a cos b}{cos a cos b} - dfrac{sin a sin b}{cos a cos b}}\[1ex]

&=frac{dfrac{sin a}{cos a} + dfrac{sin b}{cos b}}

       {1 - dfrac{sin a sin b}{cos a cos b}}                                   \[1ex]

    &=frac{tan a +tan b }{1 - tan a tan b}

end{align*}

end{document}

share|improve this answer

answered 13 mins ago

ZarkoZarko

125k867164

answered 13 mins ago

ZarkoZarko

125k867164

answered 13 mins ago

ZarkoZarko

125k867164