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Calculating the strength of an ionic bond that contains poly-atomic ions


Why does NaCl dissolve in H2O despite its strong ionic bond?Understanding the bond dissociation energy of poly-atomic moleculesDoes the activity product decrease with increasing ionic strength?Calculating the ionic product of waterCalculating the ionic polarizability from the Clausius-Mossoti relationAtomic orbitals: how is bond strength related to stability, energy, bond length?The impossibility of 100% ionic bondCalculating the enthalpy of polymerisation of ethylene given the bond strengthsExplanation of the strength of phosphorus-oxygen bondIs there a website or book that contains accepted values for the enthalpy change of the reactions between acids and bases?













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So the bond association enthalpy for ionic compounds like $ce{NaCl}$ and $ce{NaBr}$ can be easily calculated from a Born-Haber cycle. But the way a Born-Haber cycle is constructed it uses info that only really applies to mono-atomic ions like $ce{Cl^-}$. So how would one calculate the strength of an ionic bond for ionic salts that contain poly-atomic ions like $ce{NaOH}$ and $ce{K_2SO_4}$. Is there a completely different method, or can a Born-Haber cycle be adapted to use a poly-atomic ion?










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$endgroup$

















    2












    $begingroup$


    So the bond association enthalpy for ionic compounds like $ce{NaCl}$ and $ce{NaBr}$ can be easily calculated from a Born-Haber cycle. But the way a Born-Haber cycle is constructed it uses info that only really applies to mono-atomic ions like $ce{Cl^-}$. So how would one calculate the strength of an ionic bond for ionic salts that contain poly-atomic ions like $ce{NaOH}$ and $ce{K_2SO_4}$. Is there a completely different method, or can a Born-Haber cycle be adapted to use a poly-atomic ion?










    share|improve this question











    $endgroup$















      2












      2








      2





      $begingroup$


      So the bond association enthalpy for ionic compounds like $ce{NaCl}$ and $ce{NaBr}$ can be easily calculated from a Born-Haber cycle. But the way a Born-Haber cycle is constructed it uses info that only really applies to mono-atomic ions like $ce{Cl^-}$. So how would one calculate the strength of an ionic bond for ionic salts that contain poly-atomic ions like $ce{NaOH}$ and $ce{K_2SO_4}$. Is there a completely different method, or can a Born-Haber cycle be adapted to use a poly-atomic ion?










      share|improve this question











      $endgroup$




      So the bond association enthalpy for ionic compounds like $ce{NaCl}$ and $ce{NaBr}$ can be easily calculated from a Born-Haber cycle. But the way a Born-Haber cycle is constructed it uses info that only really applies to mono-atomic ions like $ce{Cl^-}$. So how would one calculate the strength of an ionic bond for ionic salts that contain poly-atomic ions like $ce{NaOH}$ and $ce{K_2SO_4}$. Is there a completely different method, or can a Born-Haber cycle be adapted to use a poly-atomic ion?







      physical-chemistry thermodynamics enthalpy ionic-compounds solid-state-chemistry






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      edited 38 mins ago









      andselisk

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          $begingroup$

          With enough effort, Born–Haber cycle can be extended to polyatomic ionic solids, however it's practically never done in practice due to the lack of experimental data or because it's impossible to obtain any.



          From [1, p. 118] (emphasis mine):




          $$U = ΔH_mathrm{f} - left(ΔH_mathrm{s} + frac{1}{2}D + IE + EAright)$$



          One difficulty with using a Born–Haber cycle to find values for $U$ is that heats of formation data are often unavailable. Perhaps the greatest limitation, however, is that electron affinities for multiply-charged anions (e.g. $ce{O^2-}$) or polyanions (e.g. $ce{SiO4^4-}$) cannot be experimentally obtained. Such anions simply do not exist as gaseous species. No atom has a positive second electron affinity; energy must be added to a negatively charged gaseous species in order for it to accommodate additional electrons. In some cases, thermochemical estimates for second and third electron affinities are available from ab initio calculations. Even so, if there are large covalent forces in the crystal, poor agreement between the values of $U$ obtained from a Born–Haber cycle and Madelung calculations can be expected.




          References




          1. Lalena, J. N.; Cleary, D. A. Principles of Inorganic Materials Design, 2nd ed.; John Wiley: Hoboken, N.J, 2010. ISBN 978-0-470-40403-4.






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            1 Answer
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            $begingroup$

            With enough effort, Born–Haber cycle can be extended to polyatomic ionic solids, however it's practically never done in practice due to the lack of experimental data or because it's impossible to obtain any.



            From [1, p. 118] (emphasis mine):




            $$U = ΔH_mathrm{f} - left(ΔH_mathrm{s} + frac{1}{2}D + IE + EAright)$$



            One difficulty with using a Born–Haber cycle to find values for $U$ is that heats of formation data are often unavailable. Perhaps the greatest limitation, however, is that electron affinities for multiply-charged anions (e.g. $ce{O^2-}$) or polyanions (e.g. $ce{SiO4^4-}$) cannot be experimentally obtained. Such anions simply do not exist as gaseous species. No atom has a positive second electron affinity; energy must be added to a negatively charged gaseous species in order for it to accommodate additional electrons. In some cases, thermochemical estimates for second and third electron affinities are available from ab initio calculations. Even so, if there are large covalent forces in the crystal, poor agreement between the values of $U$ obtained from a Born–Haber cycle and Madelung calculations can be expected.




            References




            1. Lalena, J. N.; Cleary, D. A. Principles of Inorganic Materials Design, 2nd ed.; John Wiley: Hoboken, N.J, 2010. ISBN 978-0-470-40403-4.






            share|improve this answer









            $endgroup$


















              2












              $begingroup$

              With enough effort, Born–Haber cycle can be extended to polyatomic ionic solids, however it's practically never done in practice due to the lack of experimental data or because it's impossible to obtain any.



              From [1, p. 118] (emphasis mine):




              $$U = ΔH_mathrm{f} - left(ΔH_mathrm{s} + frac{1}{2}D + IE + EAright)$$



              One difficulty with using a Born–Haber cycle to find values for $U$ is that heats of formation data are often unavailable. Perhaps the greatest limitation, however, is that electron affinities for multiply-charged anions (e.g. $ce{O^2-}$) or polyanions (e.g. $ce{SiO4^4-}$) cannot be experimentally obtained. Such anions simply do not exist as gaseous species. No atom has a positive second electron affinity; energy must be added to a negatively charged gaseous species in order for it to accommodate additional electrons. In some cases, thermochemical estimates for second and third electron affinities are available from ab initio calculations. Even so, if there are large covalent forces in the crystal, poor agreement between the values of $U$ obtained from a Born–Haber cycle and Madelung calculations can be expected.




              References




              1. Lalena, J. N.; Cleary, D. A. Principles of Inorganic Materials Design, 2nd ed.; John Wiley: Hoboken, N.J, 2010. ISBN 978-0-470-40403-4.






              share|improve this answer









              $endgroup$
















                2












                2








                2





                $begingroup$

                With enough effort, Born–Haber cycle can be extended to polyatomic ionic solids, however it's practically never done in practice due to the lack of experimental data or because it's impossible to obtain any.



                From [1, p. 118] (emphasis mine):




                $$U = ΔH_mathrm{f} - left(ΔH_mathrm{s} + frac{1}{2}D + IE + EAright)$$



                One difficulty with using a Born–Haber cycle to find values for $U$ is that heats of formation data are often unavailable. Perhaps the greatest limitation, however, is that electron affinities for multiply-charged anions (e.g. $ce{O^2-}$) or polyanions (e.g. $ce{SiO4^4-}$) cannot be experimentally obtained. Such anions simply do not exist as gaseous species. No atom has a positive second electron affinity; energy must be added to a negatively charged gaseous species in order for it to accommodate additional electrons. In some cases, thermochemical estimates for second and third electron affinities are available from ab initio calculations. Even so, if there are large covalent forces in the crystal, poor agreement between the values of $U$ obtained from a Born–Haber cycle and Madelung calculations can be expected.




                References




                1. Lalena, J. N.; Cleary, D. A. Principles of Inorganic Materials Design, 2nd ed.; John Wiley: Hoboken, N.J, 2010. ISBN 978-0-470-40403-4.






                share|improve this answer









                $endgroup$



                With enough effort, Born–Haber cycle can be extended to polyatomic ionic solids, however it's practically never done in practice due to the lack of experimental data or because it's impossible to obtain any.



                From [1, p. 118] (emphasis mine):




                $$U = ΔH_mathrm{f} - left(ΔH_mathrm{s} + frac{1}{2}D + IE + EAright)$$



                One difficulty with using a Born–Haber cycle to find values for $U$ is that heats of formation data are often unavailable. Perhaps the greatest limitation, however, is that electron affinities for multiply-charged anions (e.g. $ce{O^2-}$) or polyanions (e.g. $ce{SiO4^4-}$) cannot be experimentally obtained. Such anions simply do not exist as gaseous species. No atom has a positive second electron affinity; energy must be added to a negatively charged gaseous species in order for it to accommodate additional electrons. In some cases, thermochemical estimates for second and third electron affinities are available from ab initio calculations. Even so, if there are large covalent forces in the crystal, poor agreement between the values of $U$ obtained from a Born–Haber cycle and Madelung calculations can be expected.




                References




                1. Lalena, J. N.; Cleary, D. A. Principles of Inorganic Materials Design, 2nd ed.; John Wiley: Hoboken, N.J, 2010. ISBN 978-0-470-40403-4.







                share|improve this answer












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                share|improve this answer










                answered 38 mins ago









                andseliskandselisk

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