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Will the duration of traveling to Ceres using the same tech developed for going to Mars be proportional to the distance to go to Mars or not?

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Will the duration of traveling to Ceres using the same tech developed for going to Mars be proportional to the distance to go to Mars or not?

Does a mission to Venus orbit require less propellant than a similar mission to Mars?How do we make a round-trip journey to Mars?Gradulated Accelerated TransferWhy can't we use the same radiation shielding in Mars that we used when going to the moon?Color-correcting photos on Mars so that things look like they would on Earth - is it a big correction?Does variable distance to Mars affect data transmission rates?What will the US send to Mars as mentioned in this statement to the press?How can I verify my reconstructed gravity field of Ceres from spherical harmonics?How long will it take to develop the technologies necessary for a Mars Mission?Terraform via moving Ceres To Mars orbit, using ion drive

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I've read somewhere (I dont have right now the source and I dont know if it's trustworthy) that something that would take a significant amount of time for going to Mars would be the acceleration and deceleration process. If this is the case, a travel to a larger distance using the same technology could be not proportional to the distance . Is this so? Will the duration of traveling to Ceres using the same technology developed for going to Mars be proportional to the distance employed for going to Mars or not? If it isnt proportional what would it be, shorter or larger?

spacex mars ceres

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PabloPablo

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2

1

$begingroup$

I've read somewhere (I dont have right now the source and I dont know if it's trustworthy) that something that would take a significant amount of time for going to Mars would be the acceleration and deceleration process. If this is the case, a travel to a larger distance using the same technology could be not proportional to the distance . Is this so? Will the duration of traveling to Ceres using the same technology developed for going to Mars be proportional to the distance employed for going to Mars or not? If it isnt proportional what would it be, shorter or larger?

spacex mars ceres

share|improve this question

asked 3 hours ago

PabloPablo

1274

New contributor

Pablo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

$begingroup$

I've read somewhere (I dont have right now the source and I dont know if it's trustworthy) that something that would take a significant amount of time for going to Mars would be the acceleration and deceleration process. If this is the case, a travel to a larger distance using the same technology could be not proportional to the distance . Is this so? Will the duration of traveling to Ceres using the same technology developed for going to Mars be proportional to the distance employed for going to Mars or not? If it isnt proportional what would it be, shorter or larger?

spacex mars ceres

share|improve this question

asked 3 hours ago

PabloPablo

1274

New contributor

Pablo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

share|improve this question

asked 3 hours ago

PabloPablo

1274

New contributor

Pablo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 3 hours ago

PabloPablo

1274

New contributor

Pablo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 3 hours ago

PabloPablo

1274

New contributor

Pablo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 3 hours ago

PabloPablo

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1 Answer
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Planning travel within the solar system doesn't work quite like you assume. A spacecraft typically uses its rockets for a few minutes at the start and end of the journey and coasts the rest of the way, but while it is coasting the gravity of the planets it leaving or approaching, and much more importantly the Sun act to change its direction and velocity.

To go from Earth to Ceres, you need to initially travel faster than you do to get to Mars, otherwise you will not be going fast enough to get that far away from the Sun before the Sun's gravity slows you down and starts pulling you in.

There are lots of possible times to depart and arrive, each of which needs a different amount of rocket propulsion. These are conveniently gathered in something called a "pork chop plot". You can calculate them online

For instance for Mars you might get:

This shows departure dates on the x axis, flight times on the y axis and the fuel needed (for the departure from Earth at least, but you can aerobrake on arrival) by the colour.

For Ceres you get:

So the most fuel efficient journeys need almost twice as much fuel (more because you can't aerobrake) and take about twice as long.

share|improve this answer

answered 2 hours ago

Steve LintonSteve Linton

7,60511943

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4

$begingroup$

Planning travel within the solar system doesn't work quite like you assume. A spacecraft typically uses its rockets for a few minutes at the start and end of the journey and coasts the rest of the way, but while it is coasting the gravity of the planets it leaving or approaching, and much more importantly the Sun act to change its direction and velocity.

To go from Earth to Ceres, you need to initially travel faster than you do to get to Mars, otherwise you will not be going fast enough to get that far away from the Sun before the Sun's gravity slows you down and starts pulling you in.

There are lots of possible times to depart and arrive, each of which needs a different amount of rocket propulsion. These are conveniently gathered in something called a "pork chop plot". You can calculate them online

For instance for Mars you might get:

This shows departure dates on the x axis, flight times on the y axis and the fuel needed (for the departure from Earth at least, but you can aerobrake on arrival) by the colour.

For Ceres you get:

So the most fuel efficient journeys need almost twice as much fuel (more because you can't aerobrake) and take about twice as long.

share|improve this answer

answered 2 hours ago

Steve LintonSteve Linton

7,60511943

$endgroup$

add a comment | 

4

$begingroup$

Planning travel within the solar system doesn't work quite like you assume. A spacecraft typically uses its rockets for a few minutes at the start and end of the journey and coasts the rest of the way, but while it is coasting the gravity of the planets it leaving or approaching, and much more importantly the Sun act to change its direction and velocity.

To go from Earth to Ceres, you need to initially travel faster than you do to get to Mars, otherwise you will not be going fast enough to get that far away from the Sun before the Sun's gravity slows you down and starts pulling you in.

There are lots of possible times to depart and arrive, each of which needs a different amount of rocket propulsion. These are conveniently gathered in something called a "pork chop plot". You can calculate them online

For instance for Mars you might get:

This shows departure dates on the x axis, flight times on the y axis and the fuel needed (for the departure from Earth at least, but you can aerobrake on arrival) by the colour.

For Ceres you get:

So the most fuel efficient journeys need almost twice as much fuel (more because you can't aerobrake) and take about twice as long.

share|improve this answer

answered 2 hours ago

Steve LintonSteve Linton

7,60511943

$endgroup$

add a comment | 

$begingroup$

Planning travel within the solar system doesn't work quite like you assume. A spacecraft typically uses its rockets for a few minutes at the start and end of the journey and coasts the rest of the way, but while it is coasting the gravity of the planets it leaving or approaching, and much more importantly the Sun act to change its direction and velocity.

To go from Earth to Ceres, you need to initially travel faster than you do to get to Mars, otherwise you will not be going fast enough to get that far away from the Sun before the Sun's gravity slows you down and starts pulling you in.

There are lots of possible times to depart and arrive, each of which needs a different amount of rocket propulsion. These are conveniently gathered in something called a "pork chop plot". You can calculate them online

For instance for Mars you might get:

This shows departure dates on the x axis, flight times on the y axis and the fuel needed (for the departure from Earth at least, but you can aerobrake on arrival) by the colour.

For Ceres you get:

So the most fuel efficient journeys need almost twice as much fuel (more because you can't aerobrake) and take about twice as long.

share|improve this answer

answered 2 hours ago

Steve LintonSteve Linton

7,60511943

$endgroup$

share|improve this answer

answered 2 hours ago

Steve LintonSteve Linton

7,60511943

answered 2 hours ago

Steve LintonSteve Linton

7,60511943

answered 2 hours ago

Steve LintonSteve Linton

7,60511943