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Is it possible to set values for a list of variables using a for loop?
Assign one button to two variablesAssign variable's value programmaticallyUnderstanding Function and Variable in Mathematica for beginnerReplacing multiple instances of a symbol with different variables and assignmentsAppend fixed value to random selection of listUsing delayed evaluation on module variables called through an associationHow can I assign many values each to a different variable?How to return the unevaluated variable names from a list of variables which have been declaredAssignment via iteration over list of variables to be assigned valuesWriting a variable to file with its value, not its name
$begingroup$
Let me preface this question by noting that this is a simple example meant to clarify what I am asking. The actual context in which I want to implement this involves associations containing hundreds of variables, nested for loops, and writing to/reading from files. Because of this, the traditional method of setting a list of variables to a list of values (e.g. {a,b,c}={1,2,3}) is not practical.
Here is my simplified example:
Suppose I have a list of variables which have already been defined: a,b,c,d,e,f. I want to set these variables to values of 1,2,3,4,5,6 using a for loop.
To do this, I define the list:
listOfVar = {"a","b","c","d","e","f"}
And naively use the following for loop
For[i=1,i<=listOfVar,i++,
listOfVar[[i]] = i
]
Clearly, this won't work, as it will just set
listOfVar = {1,2,3,4,5}
My question is thus:
How do I replace listOfVar[[i]] with the variable name which its string represents? (e.g. how do I replace listOfVar[[3]] with the variable c so that the for loop correctly sets c to the value of 3?)
I have tried many combinations of Hold[],ToExpression[],ToString[],etc., but I do not seem to have enough knowledge of the low-level operations of Mathematica to solve this problem (or perhaps I am overlooking an obvious solution for whatever reason). I would greatly appreciate the help, as this is a problem I have given up on multiple times.
assignment
edited 1 hour ago
Henrik Schumacher
54.6k474153
asked 2 hours ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
$begingroup$
Let me preface this question by noting that this is a simple example meant to clarify what I am asking. The actual context in which I want to implement this involves associations containing hundreds of variables, nested for loops, and writing to/reading from files. Because of this, the traditional method of setting a list of variables to a list of values (e.g. {a,b,c}={1,2,3}) is not practical.
Here is my simplified example:
Suppose I have a list of variables which have already been defined: a,b,c,d,e,f. I want to set these variables to values of 1,2,3,4,5,6 using a for loop.
To do this, I define the list:
listOfVar = {"a","b","c","d","e","f"}
And naively use the following for loop
For[i=1,i<=listOfVar,i++,
listOfVar[[i]] = i
]
Clearly, this won't work, as it will just set
listOfVar = {1,2,3,4,5}
My question is thus:
How do I replace listOfVar[[i]] with the variable name which its string represents? (e.g. how do I replace listOfVar[[3]] with the variable c so that the for loop correctly sets c to the value of 3?)
I have tried many combinations of Hold[],ToExpression[],ToString[],etc., but I do not seem to have enough knowledge of the low-level operations of Mathematica to solve this problem (or perhaps I am overlooking an obvious solution for whatever reason). I would greatly appreciate the help, as this is a problem I have given up on multiple times.
assignment
edited 1 hour ago
Henrik Schumacher
54.6k474153
asked 2 hours ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Let me preface this question by noting that this is a simple example meant to clarify what I am asking. The actual context in which I want to implement this involves associations containing hundreds of variables, nested for loops, and writing to/reading from files. Because of this, the traditional method of setting a list of variables to a list of values (e.g. {a,b,c}={1,2,3}) is not practical.
Here is my simplified example:
Suppose I have a list of variables which have already been defined: a,b,c,d,e,f. I want to set these variables to values of 1,2,3,4,5,6 using a for loop.
To do this, I define the list:
listOfVar = {"a","b","c","d","e","f"}
And naively use the following for loop
For[i=1,i<=listOfVar,i++,
listOfVar[[i]] = i
]
Clearly, this won't work, as it will just set
listOfVar = {1,2,3,4,5}
My question is thus:
How do I replace listOfVar[[i]] with the variable name which its string represents? (e.g. how do I replace listOfVar[[3]] with the variable c so that the for loop correctly sets c to the value of 3?)
I have tried many combinations of Hold[],ToExpression[],ToString[],etc., but I do not seem to have enough knowledge of the low-level operations of Mathematica to solve this problem (or perhaps I am overlooking an obvious solution for whatever reason). I would greatly appreciate the help, as this is a problem I have given up on multiple times.
assignment
edited 1 hour ago
Henrik Schumacher
54.6k474153
asked 2 hours ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Let me preface this question by noting that this is a simple example meant to clarify what I am asking. The actual context in which I want to implement this involves associations containing hundreds of variables, nested for loops, and writing to/reading from files. Because of this, the traditional method of setting a list of variables to a list of values (e.g. {a,b,c}={1,2,3}) is not practical.
Here is my simplified example:
Suppose I have a list of variables which have already been defined: a,b,c,d,e,f. I want to set these variables to values of 1,2,3,4,5,6 using a for loop.
To do this, I define the list:
listOfVar = {"a","b","c","d","e","f"}
And naively use the following for loop
For[i=1,i<=listOfVar,i++,
listOfVar[[i]] = i
]
Clearly, this won't work, as it will just set
listOfVar = {1,2,3,4,5}
My question is thus:
How do I replace listOfVar[[i]] with the variable name which its string represents? (e.g. how do I replace listOfVar[[3]] with the variable c so that the for loop correctly sets c to the value of 3?)
I have tried many combinations of Hold[],ToExpression[],ToString[],etc., but I do not seem to have enough knowledge of the low-level operations of Mathematica to solve this problem (or perhaps I am overlooking an obvious solution for whatever reason). I would greatly appreciate the help, as this is a problem I have given up on multiple times.
assignment
assignment
edited 1 hour ago
Henrik Schumacher
54.6k474153
asked 2 hours ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Henrik Schumacher
54.6k474153
asked 2 hours ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Henrik Schumacher
54.6k474153
edited 1 hour ago
Henrik Schumacher
54.6k474153
edited 1 hour ago
Henrik Schumacher
54.6k474153
54.6k474153
asked 2 hours ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
user63017user63017
405
asked 2 hours ago
user63017user63017
405
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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2 Answers
2
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$begingroup$
listOfVar = {"a", "b", "c", "d", "e", "f"};
ClearAll @@ listOfVar;
Do[
ToExpression[listOfVar[[i]], InputForm, Set[#, i] &],
{i, 1, Length[listOfVar]}
];
Symbol /@ listOfVar
{1, 2, 3, 4, 5, 6}
answered 1 hour ago
Henrik SchumacherHenrik Schumacher
54.6k474153
$endgroup$
add a comment |
$begingroup$
Here is a second answer, if anyone is curious. It is a modification of an answer to another question I found after searching for an hour or two.
ClearAll @@ listOfVar;
For[i = 1, i <= Length[listOfVar], i++,
Evaluate[Symbol[listOfSavedVariables[[i]]]] = i;
]
answered 24 mins ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
listOfVar = {"a", "b", "c", "d", "e", "f"};
ClearAll @@ listOfVar;
Do[
ToExpression[listOfVar[[i]], InputForm, Set[#, i] &],
{i, 1, Length[listOfVar]}
];
Symbol /@ listOfVar
{1, 2, 3, 4, 5, 6}
answered 1 hour ago
Henrik SchumacherHenrik Schumacher
54.6k474153
$endgroup$
add a comment |
$begingroup$
listOfVar = {"a", "b", "c", "d", "e", "f"};
ClearAll @@ listOfVar;
Do[
ToExpression[listOfVar[[i]], InputForm, Set[#, i] &],
{i, 1, Length[listOfVar]}
];
Symbol /@ listOfVar
{1, 2, 3, 4, 5, 6}
answered 1 hour ago
Henrik SchumacherHenrik Schumacher
54.6k474153
$endgroup$
add a comment |
$begingroup$
listOfVar = {"a", "b", "c", "d", "e", "f"};
ClearAll @@ listOfVar;
Do[
ToExpression[listOfVar[[i]], InputForm, Set[#, i] &],
{i, 1, Length[listOfVar]}
];
Symbol /@ listOfVar
{1, 2, 3, 4, 5, 6}
answered 1 hour ago
Henrik SchumacherHenrik Schumacher
54.6k474153
$endgroup$
listOfVar = {"a", "b", "c", "d", "e", "f"};
ClearAll @@ listOfVar;
Do[
ToExpression[listOfVar[[i]], InputForm, Set[#, i] &],
{i, 1, Length[listOfVar]}
];
Symbol /@ listOfVar
{1, 2, 3, 4, 5, 6}
answered 1 hour ago
Henrik SchumacherHenrik Schumacher
54.6k474153
answered 1 hour ago
Henrik SchumacherHenrik Schumacher
54.6k474153
answered 1 hour ago
Henrik SchumacherHenrik Schumacher
54.6k474153
answered 1 hour ago
Henrik SchumacherHenrik Schumacher
54.6k474153
54.6k474153
add a comment |
add a comment |
$begingroup$
Here is a second answer, if anyone is curious. It is a modification of an answer to another question I found after searching for an hour or two.
ClearAll @@ listOfVar;
For[i = 1, i <= Length[listOfVar], i++,
Evaluate[Symbol[listOfSavedVariables[[i]]]] = i;
]
answered 24 mins ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Here is a second answer, if anyone is curious. It is a modification of an answer to another question I found after searching for an hour or two.
ClearAll @@ listOfVar;
For[i = 1, i <= Length[listOfVar], i++,
Evaluate[Symbol[listOfSavedVariables[[i]]]] = i;
]
answered 24 mins ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Here is a second answer, if anyone is curious. It is a modification of an answer to another question I found after searching for an hour or two.
ClearAll @@ listOfVar;
For[i = 1, i <= Length[listOfVar], i++,
Evaluate[Symbol[listOfSavedVariables[[i]]]] = i;
]
answered 24 mins ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Here is a second answer, if anyone is curious. It is a modification of an answer to another question I found after searching for an hour or two.
ClearAll @@ listOfVar;
For[i = 1, i <= Length[listOfVar], i++,
Evaluate[Symbol[listOfSavedVariables[[i]]]] = i;
]
answered 24 mins ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 19 mins ago
answered 24 mins ago
user63017user63017
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 24 mins ago
user63017user63017
405
answered 24 mins ago
user63017user63017
405
405
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
user63017 is a new contributor. Be nice, and check out our Code of Conduct.
user63017 is a new contributor. Be nice, and check out our Code of Conduct.
user63017 is a new contributor. Be nice, and check out our Code of Conduct.
user63017 is a new contributor. Be nice, and check out our Code of Conduct.
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