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Is it possible to set values for a list of variables using a for loop?


Assign one button to two variablesAssign variable's value programmaticallyUnderstanding Function and Variable in Mathematica for beginnerReplacing multiple instances of a symbol with different variables and assignmentsAppend fixed value to random selection of listUsing delayed evaluation on module variables called through an associationHow can I assign many values each to a different variable?How to return the unevaluated variable names from a list of variables which have been declaredAssignment via iteration over list of variables to be assigned valuesWriting a variable to file with its value, not its name













1












$begingroup$


Let me preface this question by noting that this is a simple example meant to clarify what I am asking. The actual context in which I want to implement this involves associations containing hundreds of variables, nested for loops, and writing to/reading from files. Because of this, the traditional method of setting a list of variables to a list of values (e.g. {a,b,c}={1,2,3}) is not practical.



Here is my simplified example:



Suppose I have a list of variables which have already been defined: a,b,c,d,e,f. I want to set these variables to values of 1,2,3,4,5,6 using a for loop.



To do this, I define the list:



listOfVar = {"a","b","c","d","e","f"}


And naively use the following for loop



For[i=1,i<=listOfVar,i++,

  listOfVar[[i]] = i

]


Clearly, this won't work, as it will just set



listOfVar = {1,2,3,4,5}


My question is thus:



How do I replace listOfVar[[i]] with the variable name which its string represents? (e.g. how do I replace listOfVar[[3]] with the variable c so that the for loop correctly sets c to the value of 3?)



I have tried many combinations of Hold[],ToExpression[],ToString[],etc., but I do not seem to have enough knowledge of the low-level operations of Mathematica to solve this problem (or perhaps I am overlooking an obvious solution for whatever reason). I would greatly appreciate the help, as this is a problem I have given up on multiple times.






assignment







share|improve this question









New contributor




user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$

















    1












    $begingroup$


    Let me preface this question by noting that this is a simple example meant to clarify what I am asking. The actual context in which I want to implement this involves associations containing hundreds of variables, nested for loops, and writing to/reading from files. Because of this, the traditional method of setting a list of variables to a list of values (e.g. {a,b,c}={1,2,3}) is not practical.



    Here is my simplified example:



    Suppose I have a list of variables which have already been defined: a,b,c,d,e,f. I want to set these variables to values of 1,2,3,4,5,6 using a for loop.



    To do this, I define the list:



    listOfVar = {"a","b","c","d","e","f"}


    And naively use the following for loop



    For[i=1,i<=listOfVar,i++,
    
  listOfVar[[i]] = i
    
]


    Clearly, this won't work, as it will just set



    listOfVar = {1,2,3,4,5}


    My question is thus:



    How do I replace listOfVar[[i]] with the variable name which its string represents? (e.g. how do I replace listOfVar[[3]] with the variable c so that the for loop correctly sets c to the value of 3?)



    I have tried many combinations of Hold[],ToExpression[],ToString[],etc., but I do not seem to have enough knowledge of the low-level operations of Mathematica to solve this problem (or perhaps I am overlooking an obvious solution for whatever reason). I would greatly appreciate the help, as this is a problem I have given up on multiple times.






    assignment







    share|improve this question









    New contributor




    user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      1












      1








      1





      $begingroup$


      Let me preface this question by noting that this is a simple example meant to clarify what I am asking. The actual context in which I want to implement this involves associations containing hundreds of variables, nested for loops, and writing to/reading from files. Because of this, the traditional method of setting a list of variables to a list of values (e.g. {a,b,c}={1,2,3}) is not practical.



      Here is my simplified example:



      Suppose I have a list of variables which have already been defined: a,b,c,d,e,f. I want to set these variables to values of 1,2,3,4,5,6 using a for loop.



      To do this, I define the list:



      listOfVar = {"a","b","c","d","e","f"}


      And naively use the following for loop



      For[i=1,i<=listOfVar,i++,
      
  listOfVar[[i]] = i
      
]


      Clearly, this won't work, as it will just set



      listOfVar = {1,2,3,4,5}


      My question is thus:



      How do I replace listOfVar[[i]] with the variable name which its string represents? (e.g. how do I replace listOfVar[[3]] with the variable c so that the for loop correctly sets c to the value of 3?)



      I have tried many combinations of Hold[],ToExpression[],ToString[],etc., but I do not seem to have enough knowledge of the low-level operations of Mathematica to solve this problem (or perhaps I am overlooking an obvious solution for whatever reason). I would greatly appreciate the help, as this is a problem I have given up on multiple times.






      assignment







      share|improve this question









      New contributor




      user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      Let me preface this question by noting that this is a simple example meant to clarify what I am asking. The actual context in which I want to implement this involves associations containing hundreds of variables, nested for loops, and writing to/reading from files. Because of this, the traditional method of setting a list of variables to a list of values (e.g. {a,b,c}={1,2,3}) is not practical.



      Here is my simplified example:



      Suppose I have a list of variables which have already been defined: a,b,c,d,e,f. I want to set these variables to values of 1,2,3,4,5,6 using a for loop.



      To do this, I define the list:



      listOfVar = {"a","b","c","d","e","f"}


      And naively use the following for loop



      For[i=1,i<=listOfVar,i++,
      
  listOfVar[[i]] = i
      
]


      Clearly, this won't work, as it will just set



      listOfVar = {1,2,3,4,5}


      My question is thus:



      How do I replace listOfVar[[i]] with the variable name which its string represents? (e.g. how do I replace listOfVar[[3]] with the variable c so that the for loop correctly sets c to the value of 3?)



      I have tried many combinations of Hold[],ToExpression[],ToString[],etc., but I do not seem to have enough knowledge of the low-level operations of Mathematica to solve this problem (or perhaps I am overlooking an obvious solution for whatever reason). I would greatly appreciate the help, as this is a problem I have given up on multiple times.






      assignment




      assignment






      share|improve this question









      New contributor




      user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 1 hour ago









      Henrik Schumacher

      54.6k474153




      54.6k474153






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      asked 2 hours ago









      user63017user63017

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          2 Answers
          2






          active

          oldest

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          3












          $begingroup$

          listOfVar = {"a", "b", "c", "d", "e", "f"};
          
ClearAll @@ listOfVar;
          
Do[
          
 ToExpression[listOfVar[[i]], InputForm, Set[#, i] &], 
          
 {i, 1, Length[listOfVar]}
          
 ];
          
Symbol /@ listOfVar



          {1, 2, 3, 4, 5, 6}







          share|improve this answer









          $endgroup$





















            1












            $begingroup$

            Here is a second answer, if anyone is curious. It is a modification of an answer to another question I found after searching for an hour or two.



            ClearAll @@ listOfVar;
            
  For[i = 1, i <= Length[listOfVar], i++,
            
  Evaluate[Symbol[listOfSavedVariables[[i]]]] = i;
            
]





            share|improve this answer










            New contributor




            user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$













              Your Answer





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              2 Answers
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              2 Answers
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              3












              $begingroup$

              listOfVar = {"a", "b", "c", "d", "e", "f"};
              
ClearAll @@ listOfVar;
              
Do[
              
 ToExpression[listOfVar[[i]], InputForm, Set[#, i] &], 
              
 {i, 1, Length[listOfVar]}
              
 ];
              
Symbol /@ listOfVar



              {1, 2, 3, 4, 5, 6}







              share|improve this answer









              $endgroup$


















                3












                $begingroup$

                listOfVar = {"a", "b", "c", "d", "e", "f"};
                
ClearAll @@ listOfVar;
                
Do[
                
 ToExpression[listOfVar[[i]], InputForm, Set[#, i] &], 
                
 {i, 1, Length[listOfVar]}
                
 ];
                
Symbol /@ listOfVar



                {1, 2, 3, 4, 5, 6}







                share|improve this answer









                $endgroup$
















                  3












                  3








                  3





                  $begingroup$

                  listOfVar = {"a", "b", "c", "d", "e", "f"};
                  
ClearAll @@ listOfVar;
                  
Do[
                  
 ToExpression[listOfVar[[i]], InputForm, Set[#, i] &], 
                  
 {i, 1, Length[listOfVar]}
                  
 ];
                  
Symbol /@ listOfVar



                  {1, 2, 3, 4, 5, 6}







                  share|improve this answer









                  $endgroup$



                  listOfVar = {"a", "b", "c", "d", "e", "f"};
                  
ClearAll @@ listOfVar;
                  
Do[
                  
 ToExpression[listOfVar[[i]], InputForm, Set[#, i] &], 
                  
 {i, 1, Length[listOfVar]}
                  
 ];
                  
Symbol /@ listOfVar



                  {1, 2, 3, 4, 5, 6}








                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 1 hour ago









                  Henrik SchumacherHenrik Schumacher

                  54.6k474153




                  54.6k474153























                      1












                      $begingroup$

                      Here is a second answer, if anyone is curious. It is a modification of an answer to another question I found after searching for an hour or two.



                      ClearAll @@ listOfVar;
                      
  For[i = 1, i <= Length[listOfVar], i++,
                      
  Evaluate[Symbol[listOfSavedVariables[[i]]]] = i;
                      
]





                      share|improve this answer










                      New contributor




                      user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      $endgroup$


















                        1












                        $begingroup$

                        Here is a second answer, if anyone is curious. It is a modification of an answer to another question I found after searching for an hour or two.



                        ClearAll @@ listOfVar;
                        
  For[i = 1, i <= Length[listOfVar], i++,
                        
  Evaluate[Symbol[listOfSavedVariables[[i]]]] = i;
                        
]





                        share|improve this answer










                        New contributor




                        user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                        Check out our Code of Conduct.






                        $endgroup$
















                          1












                          1








                          1





                          $begingroup$

                          Here is a second answer, if anyone is curious. It is a modification of an answer to another question I found after searching for an hour or two.



                          ClearAll @@ listOfVar;
                          
  For[i = 1, i <= Length[listOfVar], i++,
                          
  Evaluate[Symbol[listOfSavedVariables[[i]]]] = i;
                          
]





                          share|improve this answer










                          New contributor




                          user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.






                          $endgroup$



                          Here is a second answer, if anyone is curious. It is a modification of an answer to another question I found after searching for an hour or two.



                          ClearAll @@ listOfVar;
                          
  For[i = 1, i <= Length[listOfVar], i++,
                          
  Evaluate[Symbol[listOfSavedVariables[[i]]]] = i;
                          
]






                          share|improve this answer










                          New contributor




                          user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.









                          share|improve this answer



                          share|improve this answer








                          edited 19 mins ago





















                          New contributor




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                          answered 24 mins ago









                          user63017user63017

                          405




                          405




                          New contributor




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                          New contributor





                          user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                          user63017 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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