How can I deduce the power of a capacitor from its datasheet?HUGE capacitor recommended in datasheet for...

Did ancient Germans take pride in leaving the land untouched?

How can I handle players killing my NPC outside of combat?

Is the UK legally prevented from having another referendum on Brexit?

How can I give a Ranger advantage on a check due to Favored Enemy without spoiling the story for the player?

Promise.all returning empty objects

What is an efficient way to digitize a family photo collection?

Are all power cords made equal?

Is it possible to narrate a novel in a faux-historical style without alienating the reader?

How to regain lost focus?

Isn't a semicolon (';') needed after a function declaration in C++?

Is it possible to detect 100% of SQLi with a simple regex?

Why is it that Bernie Sanders is always called a "socialist"?

How bad is a Computer Science course that doesn't teach Design Patterns?

Homeostasis logic/math problem

Why do single electrical receptacles exist?

Sing Baby Shark

Using Ansible, how can I take actions on each file in a specific location?

Renting a 2CV in France

Does Plato's "Ring of Gyges" have a corrupting influence on its wearer?

What do "compile" , "fit" and "predict" do in Keras sequential models?

What's the reason that we have different quantities of days each month?

How do I add a strong "onion flavor" to the biryani (in restaurant style)?

Distribution coeffecient without concentrations

How do I avoid the "chosen hero" feeling?



How can I deduce the power of a capacitor from its datasheet?


HUGE capacitor recommended in datasheet for Audio AmpSending audio signals to output device through relayhow to select capacitor valuesCharging capacitors in parallel with a batteryCapacitor as one piece voltage controller for wind turbineHow to connect from a +/- 15v audio circuit to single powered amplifierWhat are the risks removing sleeve off the aluminium electrolytic capacitor?Need help with a push to play speaker and soundDC-DC boost converter voltage spike at power on, popping soundMeasure the power consumption of a circuit with Arduino













1












$begingroup$


I am looking for suitable capacitors for a sound amplifier I have designed.
The speaker power should be at least 7 watt (for the sound to be loud enough).
(I attach a figure of the design)



So, I think I need capacitors which are suitable for these level of power.



But, in the datasheets, i don't see any specification for the power capability of the capacitors..



Any idea how can I know I have chosen capacitors with high enough power resum capabilities?



Thanks!



enter image description here










share|improve this question









$endgroup$








  • 1




    $begingroup$
    The caps doesn't have power spec. They have capacitnce and ESR, and the voltage.
    $endgroup$
    – Marko Buršič
    1 hour ago
















1












$begingroup$


I am looking for suitable capacitors for a sound amplifier I have designed.
The speaker power should be at least 7 watt (for the sound to be loud enough).
(I attach a figure of the design)



So, I think I need capacitors which are suitable for these level of power.



But, in the datasheets, i don't see any specification for the power capability of the capacitors..



Any idea how can I know I have chosen capacitors with high enough power resum capabilities?



Thanks!



enter image description here










share|improve this question









$endgroup$








  • 1




    $begingroup$
    The caps doesn't have power spec. They have capacitnce and ESR, and the voltage.
    $endgroup$
    – Marko Buršič
    1 hour ago














1












1








1





$begingroup$


I am looking for suitable capacitors for a sound amplifier I have designed.
The speaker power should be at least 7 watt (for the sound to be loud enough).
(I attach a figure of the design)



So, I think I need capacitors which are suitable for these level of power.



But, in the datasheets, i don't see any specification for the power capability of the capacitors..



Any idea how can I know I have chosen capacitors with high enough power resum capabilities?



Thanks!



enter image description here










share|improve this question









$endgroup$




I am looking for suitable capacitors for a sound amplifier I have designed.
The speaker power should be at least 7 watt (for the sound to be loud enough).
(I attach a figure of the design)



So, I think I need capacitors which are suitable for these level of power.



But, in the datasheets, i don't see any specification for the power capability of the capacitors..



Any idea how can I know I have chosen capacitors with high enough power resum capabilities?



Thanks!



enter image description here







power capacitor energy






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 1 hour ago









user135172user135172

24029




24029








  • 1




    $begingroup$
    The caps doesn't have power spec. They have capacitnce and ESR, and the voltage.
    $endgroup$
    – Marko Buršič
    1 hour ago














  • 1




    $begingroup$
    The caps doesn't have power spec. They have capacitnce and ESR, and the voltage.
    $endgroup$
    – Marko Buršič
    1 hour ago








1




1




$begingroup$
The caps doesn't have power spec. They have capacitnce and ESR, and the voltage.
$endgroup$
– Marko Buršič
1 hour ago




$begingroup$
The caps doesn't have power spec. They have capacitnce and ESR, and the voltage.
$endgroup$
– Marko Buršič
1 hour ago










2 Answers
2






active

oldest

votes


















3












$begingroup$

Capacitors don't have power ratings because, ideally, they don't dissipate any power. They store energy unlike resistors which consume energy, giving it off as heat.



Instead, you need to consider the following:




  • The voltage rating needs to be at least that of the maximum voltage they will see in service.

  • For power regulation and loudspeaker connection electrolytics are suitable. Observe polarity.

  • The impedance of the loudspeaker decoupling capacitor needs to be low in relation to the speaker impedance. You can calculate the impedance at any frequency from the formula $ Z = frac {1}{2 pi f C} $ where Z is the impedance (ohms), f the frequency (hertz) and C the capacitor value (farads). Choose this for a reasonable bass frequency cut-off point. (Remember that frequencies below this will fall off gradually rather than a sharp cut-off.)






share|improve this answer











$endgroup$













  • $begingroup$
    Up voted this answer. @OP, On a side note, capacitors do have an internal resistance and therefore can dissipate power, but for practical reasons that is not an issue for the application described here (specifically, typical internal resistances are extremely small).
    $endgroup$
    – Digiproc
    58 mins ago



















0












$begingroup$

Regarding energy storage for the rail, consider that 1 farad when dischanged by 1 amp will sag at 1 volt/second.



Lets assume you have 50Hz power, thus you can use a full wave rectifier and have 100 recharge opportunities per second. Thus your TIME will be 0.01 seconds.



Assume you will accept 0.1 volt sag on the VDD. How big must your capacitor be?



dV/dT = I/C, derived from the derivative of Q = C * V, with C held constant.



Rearrange this, and C = I / (dV/dT) = I * T/ V



In the above case, C = 1 amp (assumed) * 0.01 second / 0.1volt= 0.1 Farad or



100,000 uF.






share|improve this answer









$endgroup$













    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("schematics", function () {
    StackExchange.schematics.init();
    });
    }, "cicuitlab");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "135"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f424095%2fhow-can-i-deduce-the-power-of-a-capacitor-from-its-datasheet%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3












    $begingroup$

    Capacitors don't have power ratings because, ideally, they don't dissipate any power. They store energy unlike resistors which consume energy, giving it off as heat.



    Instead, you need to consider the following:




    • The voltage rating needs to be at least that of the maximum voltage they will see in service.

    • For power regulation and loudspeaker connection electrolytics are suitable. Observe polarity.

    • The impedance of the loudspeaker decoupling capacitor needs to be low in relation to the speaker impedance. You can calculate the impedance at any frequency from the formula $ Z = frac {1}{2 pi f C} $ where Z is the impedance (ohms), f the frequency (hertz) and C the capacitor value (farads). Choose this for a reasonable bass frequency cut-off point. (Remember that frequencies below this will fall off gradually rather than a sharp cut-off.)






    share|improve this answer











    $endgroup$













    • $begingroup$
      Up voted this answer. @OP, On a side note, capacitors do have an internal resistance and therefore can dissipate power, but for practical reasons that is not an issue for the application described here (specifically, typical internal resistances are extremely small).
      $endgroup$
      – Digiproc
      58 mins ago
















    3












    $begingroup$

    Capacitors don't have power ratings because, ideally, they don't dissipate any power. They store energy unlike resistors which consume energy, giving it off as heat.



    Instead, you need to consider the following:




    • The voltage rating needs to be at least that of the maximum voltage they will see in service.

    • For power regulation and loudspeaker connection electrolytics are suitable. Observe polarity.

    • The impedance of the loudspeaker decoupling capacitor needs to be low in relation to the speaker impedance. You can calculate the impedance at any frequency from the formula $ Z = frac {1}{2 pi f C} $ where Z is the impedance (ohms), f the frequency (hertz) and C the capacitor value (farads). Choose this for a reasonable bass frequency cut-off point. (Remember that frequencies below this will fall off gradually rather than a sharp cut-off.)






    share|improve this answer











    $endgroup$













    • $begingroup$
      Up voted this answer. @OP, On a side note, capacitors do have an internal resistance and therefore can dissipate power, but for practical reasons that is not an issue for the application described here (specifically, typical internal resistances are extremely small).
      $endgroup$
      – Digiproc
      58 mins ago














    3












    3








    3





    $begingroup$

    Capacitors don't have power ratings because, ideally, they don't dissipate any power. They store energy unlike resistors which consume energy, giving it off as heat.



    Instead, you need to consider the following:




    • The voltage rating needs to be at least that of the maximum voltage they will see in service.

    • For power regulation and loudspeaker connection electrolytics are suitable. Observe polarity.

    • The impedance of the loudspeaker decoupling capacitor needs to be low in relation to the speaker impedance. You can calculate the impedance at any frequency from the formula $ Z = frac {1}{2 pi f C} $ where Z is the impedance (ohms), f the frequency (hertz) and C the capacitor value (farads). Choose this for a reasonable bass frequency cut-off point. (Remember that frequencies below this will fall off gradually rather than a sharp cut-off.)






    share|improve this answer











    $endgroup$



    Capacitors don't have power ratings because, ideally, they don't dissipate any power. They store energy unlike resistors which consume energy, giving it off as heat.



    Instead, you need to consider the following:




    • The voltage rating needs to be at least that of the maximum voltage they will see in service.

    • For power regulation and loudspeaker connection electrolytics are suitable. Observe polarity.

    • The impedance of the loudspeaker decoupling capacitor needs to be low in relation to the speaker impedance. You can calculate the impedance at any frequency from the formula $ Z = frac {1}{2 pi f C} $ where Z is the impedance (ohms), f the frequency (hertz) and C the capacitor value (farads). Choose this for a reasonable bass frequency cut-off point. (Remember that frequencies below this will fall off gradually rather than a sharp cut-off.)







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 50 mins ago

























    answered 1 hour ago









    TransistorTransistor

    85.3k784182




    85.3k784182












    • $begingroup$
      Up voted this answer. @OP, On a side note, capacitors do have an internal resistance and therefore can dissipate power, but for practical reasons that is not an issue for the application described here (specifically, typical internal resistances are extremely small).
      $endgroup$
      – Digiproc
      58 mins ago


















    • $begingroup$
      Up voted this answer. @OP, On a side note, capacitors do have an internal resistance and therefore can dissipate power, but for practical reasons that is not an issue for the application described here (specifically, typical internal resistances are extremely small).
      $endgroup$
      – Digiproc
      58 mins ago
















    $begingroup$
    Up voted this answer. @OP, On a side note, capacitors do have an internal resistance and therefore can dissipate power, but for practical reasons that is not an issue for the application described here (specifically, typical internal resistances are extremely small).
    $endgroup$
    – Digiproc
    58 mins ago




    $begingroup$
    Up voted this answer. @OP, On a side note, capacitors do have an internal resistance and therefore can dissipate power, but for practical reasons that is not an issue for the application described here (specifically, typical internal resistances are extremely small).
    $endgroup$
    – Digiproc
    58 mins ago













    0












    $begingroup$

    Regarding energy storage for the rail, consider that 1 farad when dischanged by 1 amp will sag at 1 volt/second.



    Lets assume you have 50Hz power, thus you can use a full wave rectifier and have 100 recharge opportunities per second. Thus your TIME will be 0.01 seconds.



    Assume you will accept 0.1 volt sag on the VDD. How big must your capacitor be?



    dV/dT = I/C, derived from the derivative of Q = C * V, with C held constant.



    Rearrange this, and C = I / (dV/dT) = I * T/ V



    In the above case, C = 1 amp (assumed) * 0.01 second / 0.1volt= 0.1 Farad or



    100,000 uF.






    share|improve this answer









    $endgroup$


















      0












      $begingroup$

      Regarding energy storage for the rail, consider that 1 farad when dischanged by 1 amp will sag at 1 volt/second.



      Lets assume you have 50Hz power, thus you can use a full wave rectifier and have 100 recharge opportunities per second. Thus your TIME will be 0.01 seconds.



      Assume you will accept 0.1 volt sag on the VDD. How big must your capacitor be?



      dV/dT = I/C, derived from the derivative of Q = C * V, with C held constant.



      Rearrange this, and C = I / (dV/dT) = I * T/ V



      In the above case, C = 1 amp (assumed) * 0.01 second / 0.1volt= 0.1 Farad or



      100,000 uF.






      share|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        Regarding energy storage for the rail, consider that 1 farad when dischanged by 1 amp will sag at 1 volt/second.



        Lets assume you have 50Hz power, thus you can use a full wave rectifier and have 100 recharge opportunities per second. Thus your TIME will be 0.01 seconds.



        Assume you will accept 0.1 volt sag on the VDD. How big must your capacitor be?



        dV/dT = I/C, derived from the derivative of Q = C * V, with C held constant.



        Rearrange this, and C = I / (dV/dT) = I * T/ V



        In the above case, C = 1 amp (assumed) * 0.01 second / 0.1volt= 0.1 Farad or



        100,000 uF.






        share|improve this answer









        $endgroup$



        Regarding energy storage for the rail, consider that 1 farad when dischanged by 1 amp will sag at 1 volt/second.



        Lets assume you have 50Hz power, thus you can use a full wave rectifier and have 100 recharge opportunities per second. Thus your TIME will be 0.01 seconds.



        Assume you will accept 0.1 volt sag on the VDD. How big must your capacitor be?



        dV/dT = I/C, derived from the derivative of Q = C * V, with C held constant.



        Rearrange this, and C = I / (dV/dT) = I * T/ V



        In the above case, C = 1 amp (assumed) * 0.01 second / 0.1volt= 0.1 Farad or



        100,000 uF.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 23 mins ago









        analogsystemsrfanalogsystemsrf

        14.8k2718




        14.8k2718






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Electrical Engineering Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f424095%2fhow-can-i-deduce-the-power-of-a-capacitor-from-its-datasheet%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Szabolcs (Ungheria) Altri progetti | Menu di navigazione48°10′14.56″N 21°29′33.14″E /...

            Discografia di Klaus Schulze Indice Album in studio | Album dal vivo | Singoli | Antologie | Colonne...

            How to make inet_server_addr() return localhost in spite of ::1/128RETURN NEXT in Postgres FunctionConnect to...