Explicit way to check whether a function was called from within the WindowIs there a better way to do...
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Explicit way to check whether a function was called from within the Window
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Is there a more explicit way of checking whether a function was called from within Window than if (typeof this.value == "undefined")
in the code below?
So that it is apparent that I am checking against Window, something like: if this.name === "Window"
.
function get_caller() {
if (typeof this.value == "undefined") {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
javascript
add a comment |
Is there a more explicit way of checking whether a function was called from within Window than if (typeof this.value == "undefined")
in the code below?
So that it is apparent that I am checking against Window, something like: if this.name === "Window"
.
function get_caller() {
if (typeof this.value == "undefined") {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
javascript
1
What happens when somebody callsget_caller.call({value: "I am not in window"})
?
– VLAZ
2 hours ago
add a comment |
Is there a more explicit way of checking whether a function was called from within Window than if (typeof this.value == "undefined")
in the code below?
So that it is apparent that I am checking against Window, something like: if this.name === "Window"
.
function get_caller() {
if (typeof this.value == "undefined") {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
javascript
Is there a more explicit way of checking whether a function was called from within Window than if (typeof this.value == "undefined")
in the code below?
So that it is apparent that I am checking against Window, something like: if this.name === "Window"
.
function get_caller() {
if (typeof this.value == "undefined") {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
function get_caller() {
if (typeof this.value == "undefined") {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
function get_caller() {
if (typeof this.value == "undefined") {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
javascript
javascript
edited 1 hour ago
barciewicz
asked 2 hours ago
barciewiczbarciewicz
665313
665313
1
What happens when somebody callsget_caller.call({value: "I am not in window"})
?
– VLAZ
2 hours ago
add a comment |
1
What happens when somebody callsget_caller.call({value: "I am not in window"})
?
– VLAZ
2 hours ago
1
1
What happens when somebody calls
get_caller.call({value: "I am not in window"})
?– VLAZ
2 hours ago
What happens when somebody calls
get_caller.call({value: "I am not in window"})
?– VLAZ
2 hours ago
add a comment |
2 Answers
2
active
oldest
votes
Just check if this
is window
:
function get_caller() {
if (this === window) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
New contributor
Orundefined
, in strict mode, which is the more common case today with webpack/modules.
– Madara Uchiha♦
58 mins ago
add a comment |
You can check if this==window
or if strict mode is on check if this
is undefined
,
function get_caller() {
"use strict"; // !this is used for strict mode check
if (this == window || !this) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just check if this
is window
:
function get_caller() {
if (this === window) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
New contributor
Orundefined
, in strict mode, which is the more common case today with webpack/modules.
– Madara Uchiha♦
58 mins ago
add a comment |
Just check if this
is window
:
function get_caller() {
if (this === window) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
New contributor
Orundefined
, in strict mode, which is the more common case today with webpack/modules.
– Madara Uchiha♦
58 mins ago
add a comment |
Just check if this
is window
:
function get_caller() {
if (this === window) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
New contributor
Just check if this
is window
:
function get_caller() {
if (this === window) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
function get_caller() {
if (this === window) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
function get_caller() {
if (this === window) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
New contributor
New contributor
answered 2 hours ago
SnowSnow
15611
15611
New contributor
New contributor
Orundefined
, in strict mode, which is the more common case today with webpack/modules.
– Madara Uchiha♦
58 mins ago
add a comment |
Orundefined
, in strict mode, which is the more common case today with webpack/modules.
– Madara Uchiha♦
58 mins ago
Or
undefined
, in strict mode, which is the more common case today with webpack/modules.– Madara Uchiha♦
58 mins ago
Or
undefined
, in strict mode, which is the more common case today with webpack/modules.– Madara Uchiha♦
58 mins ago
add a comment |
You can check if this==window
or if strict mode is on check if this
is undefined
,
function get_caller() {
"use strict"; // !this is used for strict mode check
if (this == window || !this) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
add a comment |
You can check if this==window
or if strict mode is on check if this
is undefined
,
function get_caller() {
"use strict"; // !this is used for strict mode check
if (this == window || !this) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
add a comment |
You can check if this==window
or if strict mode is on check if this
is undefined
,
function get_caller() {
"use strict"; // !this is used for strict mode check
if (this == window || !this) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
You can check if this==window
or if strict mode is on check if this
is undefined
,
function get_caller() {
"use strict"; // !this is used for strict mode check
if (this == window || !this) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
function get_caller() {
"use strict"; // !this is used for strict mode check
if (this == window || !this) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
function get_caller() {
"use strict"; // !this is used for strict mode check
if (this == window || !this) {
console.log('function get_caller called from window')
}
else {
console.log('function get_caller called by button press')
}
}
btn.addEventListener('click', get_caller)
get_caller()
<button id="btn">Get caller</button>
answered 2 hours ago
Code_ModeCode_Mode
906714
906714
add a comment |
add a comment |
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1
What happens when somebody calls
get_caller.call({value: "I am not in window"})
?– VLAZ
2 hours ago