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Not unique table/alias: 'tbl_users'














0















i have difficulties with my codes in inner join. i need to join 4 of my tables but it has a error "Not unique table/alias: 'tbl_users'" and when i added alias my table didn't recognized and its attribute.



$sqltran = mysqli_query($con, "SELECT tbl_users.userid , tbl_applicant.applicant_id,tbl_payment.userid



                                FROM `tbl_users` , `tbl_applicant` 

INNER JOIN `tbl_users` ON `tbl_users`.`userid` = `tbl_applicant`.`applicant_id`

INNER JOIN `tbl_applicant` ON `tbl_applicant.applicant_id` = `tbl_payment`.`userid`


WHERE `u_id.userid` = '".$_SESSION['userid']."'")or die(mysqli_error($con));
$arrVal = array();


thank you!!..
i'm hoping for your answers.









share







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    0















    i have difficulties with my codes in inner join. i need to join 4 of my tables but it has a error "Not unique table/alias: 'tbl_users'" and when i added alias my table didn't recognized and its attribute.



    $sqltran = mysqli_query($con, "SELECT tbl_users.userid , tbl_applicant.applicant_id,tbl_payment.userid



                                    FROM `tbl_users` , `tbl_applicant` 

    INNER JOIN `tbl_users` ON `tbl_users`.`userid` = `tbl_applicant`.`applicant_id`

    INNER JOIN `tbl_applicant` ON `tbl_applicant.applicant_id` = `tbl_payment`.`userid`


    WHERE `u_id.userid` = '".$_SESSION['userid']."'")or die(mysqli_error($con));
    $arrVal = array();


    thank you!!..
    i'm hoping for your answers.









    share







    New contributor




    Alexandra de Leon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      0












      0








      0








      i have difficulties with my codes in inner join. i need to join 4 of my tables but it has a error "Not unique table/alias: 'tbl_users'" and when i added alias my table didn't recognized and its attribute.



      $sqltran = mysqli_query($con, "SELECT tbl_users.userid , tbl_applicant.applicant_id,tbl_payment.userid



                                      FROM `tbl_users` , `tbl_applicant` 

      INNER JOIN `tbl_users` ON `tbl_users`.`userid` = `tbl_applicant`.`applicant_id`

      INNER JOIN `tbl_applicant` ON `tbl_applicant.applicant_id` = `tbl_payment`.`userid`


      WHERE `u_id.userid` = '".$_SESSION['userid']."'")or die(mysqli_error($con));
      $arrVal = array();


      thank you!!..
      i'm hoping for your answers.









      share







      New contributor




      Alexandra de Leon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      i have difficulties with my codes in inner join. i need to join 4 of my tables but it has a error "Not unique table/alias: 'tbl_users'" and when i added alias my table didn't recognized and its attribute.



      $sqltran = mysqli_query($con, "SELECT tbl_users.userid , tbl_applicant.applicant_id,tbl_payment.userid



                                      FROM `tbl_users` , `tbl_applicant` 

      INNER JOIN `tbl_users` ON `tbl_users`.`userid` = `tbl_applicant`.`applicant_id`

      INNER JOIN `tbl_applicant` ON `tbl_applicant.applicant_id` = `tbl_payment`.`userid`


      WHERE `u_id.userid` = '".$_SESSION['userid']."'")or die(mysqli_error($con));
      $arrVal = array();


      thank you!!..
      i'm hoping for your answers.







      sql-server mysql sql-server-2012





      share







      New contributor




      Alexandra de Leon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      Alexandra de Leon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






      New contributor




      Alexandra de Leon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 1 min ago









      Alexandra de LeonAlexandra de Leon

      1




      1




      New contributor




      Alexandra de Leon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Alexandra de Leon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Alexandra de Leon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















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