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1

I am learning TikZ with the pgfmanual. The example given is as follows:

I have achieved the following so far:

The code is as follows:

documentclass{article}

usepackage{tikz}



tikzset{help lines/.style=very thin}

tikzset{My Grid/.style={help lines,color=blue!50}}



begin{document}

begin{tikzpicture}

  draw[My Grid] (-4,-4) grid (4,4);

  draw (-5,0) node[left] {$(-5,0)$} -- (5,0) node[right] {$(5,0)$};

  draw (0,-5) node[below] {$(0,-5)$} -- (0,5) node[above] {$(0,5)$};

  draw (0,0)  circle [radius=3cm];

  shadedraw[left color=gray, right color=green, draw=green!50!black] (0,0) -- (0.75,0)  arc [start angle=0, end angle=30, radius=1cm] -- cycle;

  draw[red, very thick] (30:3cm) -- (2.6,0);

  draw [very thick,orange] (3,0) -- (3,1.7);

end{tikzpicture}

end{document} 

To achieve the intersection of the slope and tangent, pgfmanual uses the concept of path and intersections library which is very confusing.

Is there an easier way to tell the system to draw a line from point A to sin(30) as point B and to draw tangent of the angle proportionately instead of using direct numbers.

Please suggest alternative apart from intersections, polar coordinates and paths. Because the pgfmanual already uses them which is hard to understand.

tikz-pgf intersections

share|improve this question

edited 3 hours ago

Hafid Boukhoulda

3,9021622

asked 4 hours ago

subham sonisubham soni

3,96382981

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  May be If you specify exactly what is hard for you to understand someone will try to explain it to you
  
  – Hafid Boukhoulda
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @hafid The slope lines and connecting the tangent for the time being
  
  – subham soni
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Do you need to use cos(30) and tan(30) to indicate point coordinates instead of (2.6,0) and (3,1.7)
  
  – Hafid Boukhoulda
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes @hafid. That is exactly the requirement.
  
  – subham soni
  4 hours ago
  

  
  
  
  

add a comment | 

1

I am learning TikZ with the pgfmanual. The example given is as follows:

I have achieved the following so far:

The code is as follows:

documentclass{article}

usepackage{tikz}



tikzset{help lines/.style=very thin}

tikzset{My Grid/.style={help lines,color=blue!50}}



begin{document}

begin{tikzpicture}

  draw[My Grid] (-4,-4) grid (4,4);

  draw (-5,0) node[left] {$(-5,0)$} -- (5,0) node[right] {$(5,0)$};

  draw (0,-5) node[below] {$(0,-5)$} -- (0,5) node[above] {$(0,5)$};

  draw (0,0)  circle [radius=3cm];

  shadedraw[left color=gray, right color=green, draw=green!50!black] (0,0) -- (0.75,0)  arc [start angle=0, end angle=30, radius=1cm] -- cycle;

  draw[red, very thick] (30:3cm) -- (2.6,0);

  draw [very thick,orange] (3,0) -- (3,1.7);

end{tikzpicture}

end{document} 

To achieve the intersection of the slope and tangent, pgfmanual uses the concept of path and intersections library which is very confusing.

Is there an easier way to tell the system to draw a line from point A to sin(30) as point B and to draw tangent of the angle proportionately instead of using direct numbers.

Please suggest alternative apart from intersections, polar coordinates and paths. Because the pgfmanual already uses them which is hard to understand.

tikz-pgf intersections

share|improve this question

edited 3 hours ago

Hafid Boukhoulda

3,9021622

asked 4 hours ago

subham sonisubham soni

3,96382981

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  May be If you specify exactly what is hard for you to understand someone will try to explain it to you
  
  – Hafid Boukhoulda
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @hafid The slope lines and connecting the tangent for the time being
  
  – subham soni
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Do you need to use cos(30) and tan(30) to indicate point coordinates instead of (2.6,0) and (3,1.7)
  
  – Hafid Boukhoulda
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes @hafid. That is exactly the requirement.
  
  – subham soni
  4 hours ago
  

  
  
  
  

add a comment | 

I am learning TikZ with the pgfmanual. The example given is as follows:

I have achieved the following so far:

The code is as follows:

documentclass{article}

usepackage{tikz}



tikzset{help lines/.style=very thin}

tikzset{My Grid/.style={help lines,color=blue!50}}



begin{document}

begin{tikzpicture}

  draw[My Grid] (-4,-4) grid (4,4);

  draw (-5,0) node[left] {$(-5,0)$} -- (5,0) node[right] {$(5,0)$};

  draw (0,-5) node[below] {$(0,-5)$} -- (0,5) node[above] {$(0,5)$};

  draw (0,0)  circle [radius=3cm];

  shadedraw[left color=gray, right color=green, draw=green!50!black] (0,0) -- (0.75,0)  arc [start angle=0, end angle=30, radius=1cm] -- cycle;

  draw[red, very thick] (30:3cm) -- (2.6,0);

  draw [very thick,orange] (3,0) -- (3,1.7);

end{tikzpicture}

end{document} 

To achieve the intersection of the slope and tangent, pgfmanual uses the concept of path and intersections library which is very confusing.

Is there an easier way to tell the system to draw a line from point A to sin(30) as point B and to draw tangent of the angle proportionately instead of using direct numbers.

Please suggest alternative apart from intersections, polar coordinates and paths. Because the pgfmanual already uses them which is hard to understand.

tikz-pgf intersections

share|improve this question

edited 3 hours ago

Hafid Boukhoulda

3,9021622

asked 4 hours ago

subham sonisubham soni

3,96382981

documentclass{article}

usepackage{tikz}



tikzset{help lines/.style=very thin}

tikzset{My Grid/.style={help lines,color=blue!50}}



begin{document}

begin{tikzpicture}

  draw[My Grid] (-4,-4) grid (4,4);

  draw (-5,0) node[left] {$(-5,0)$} -- (5,0) node[right] {$(5,0)$};

  draw (0,-5) node[below] {$(0,-5)$} -- (0,5) node[above] {$(0,5)$};

  draw (0,0)  circle [radius=3cm];

  shadedraw[left color=gray, right color=green, draw=green!50!black] (0,0) -- (0.75,0)  arc [start angle=0, end angle=30, radius=1cm] -- cycle;

  draw[red, very thick] (30:3cm) -- (2.6,0);

  draw [very thick,orange] (3,0) -- (3,1.7);

end{tikzpicture}

end{document} 

share|improve this question

edited 3 hours ago

Hafid Boukhoulda

3,9021622

asked 4 hours ago

subham sonisubham soni

3,96382981

share|improve this question

edited 3 hours ago

Hafid Boukhoulda

3,9021622

asked 4 hours ago

subham sonisubham soni

3,96382981

edited 3 hours ago

Hafid Boukhoulda

3,9021622

edited 3 hours ago

Hafid Boukhoulda

3,9021622

asked 4 hours ago

subham sonisubham soni

3,96382981

asked 4 hours ago

subham sonisubham soni

3,96382981

1 Answer
1

active

oldest

votes

6

Since in cos(30) and tan(30) there are parentheses you must put these functions inside curly brackets {}

documentclass{article}

usepackage{tikz}

usetikzlibrary{angles,quotes}



tikzset{help lines/.style=very thin}

tikzset{My Grid/.style={help lines,color=blue!50}}



begin{document}

begin{tikzpicture}

  draw[My Grid] (-4,-4) grid (4,4);

  draw (-5,0) node[left] {$(-5,0)$} -- (5,0) node[right] {$(5,0)$};

  draw (0,-5) node[below] {$(0,-5)$} -- (0,5) node[above] {$(0,5)$};

  draw (0,0)  circle [radius=3cm];



%   shadedraw[left color=gray, right color=green, draw=green!50!black]

% (0,0) -- (0.75,0)  arc [start angle=0, end angle=30, radius=0.75cm] --  cycle;



  coordinate(O)at(0,0);

  draw[red, very thick] (30:3cm)coordinate(A) 

                         --({3*cos(30)},0)coordinate(B);



  draw [very thick,orange] (3,0) -- (3,{3*tan(30)})coordinate(C);



  pic[fill=green!50!black,

       angle radius=0.75cm,

       angle eccentricity=1.2,

       "(alpha)"] {angle=B--O--A};



   draw (O)--(C);



end{tikzpicture}

end{document} 

share|improve this answer

edited 1 hour ago

answered 4 hours ago

Hafid BoukhouldaHafid Boukhoulda

3,9021622

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Will this ensure that the length is actual value when computed as well or plotted manually with pencil and graph?
  
  – subham soni
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @subhamsoni I notice that the green angle is greeter than 30° I suppose you needed to be 30°
  
  – Hafid Boukhoulda
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have mentioned end angle as 30. Is there anything I am missing
  
  – subham soni
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @subhamsoni Yes you need the specify the correct radius 0.75 cm and not 1cm since the start point is (0.75,0). Also in Tikz there is another manner to draw angles.
  
  – Hafid Boukhoulda
  3 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  it would be great if you can share the other way because precision is always better.
  
  – subham soni
  3 hours ago
  

  
  
  
  

 | 
show 4 more comments

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6

Since in cos(30) and tan(30) there are parentheses you must put these functions inside curly brackets {}

documentclass{article}

usepackage{tikz}

usetikzlibrary{angles,quotes}



tikzset{help lines/.style=very thin}

tikzset{My Grid/.style={help lines,color=blue!50}}



begin{document}

begin{tikzpicture}

  draw[My Grid] (-4,-4) grid (4,4);

  draw (-5,0) node[left] {$(-5,0)$} -- (5,0) node[right] {$(5,0)$};

  draw (0,-5) node[below] {$(0,-5)$} -- (0,5) node[above] {$(0,5)$};

  draw (0,0)  circle [radius=3cm];



%   shadedraw[left color=gray, right color=green, draw=green!50!black]

% (0,0) -- (0.75,0)  arc [start angle=0, end angle=30, radius=0.75cm] --  cycle;



  coordinate(O)at(0,0);

  draw[red, very thick] (30:3cm)coordinate(A) 

                         --({3*cos(30)},0)coordinate(B);



  draw [very thick,orange] (3,0) -- (3,{3*tan(30)})coordinate(C);



  pic[fill=green!50!black,

       angle radius=0.75cm,

       angle eccentricity=1.2,

       "(alpha)"] {angle=B--O--A};



   draw (O)--(C);



end{tikzpicture}

end{document} 

share|improve this answer

edited 1 hour ago

answered 4 hours ago

Hafid BoukhouldaHafid Boukhoulda

3,9021622

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Will this ensure that the length is actual value when computed as well or plotted manually with pencil and graph?
  
  – subham soni
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @subhamsoni I notice that the green angle is greeter than 30° I suppose you needed to be 30°
  
  – Hafid Boukhoulda
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have mentioned end angle as 30. Is there anything I am missing
  
  – subham soni
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @subhamsoni Yes you need the specify the correct radius 0.75 cm and not 1cm since the start point is (0.75,0). Also in Tikz there is another manner to draw angles.
  
  – Hafid Boukhoulda
  3 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  it would be great if you can share the other way because precision is always better.
  
  – subham soni
  3 hours ago
  

  
  
  
  

 | 
show 4 more comments

6

Since in cos(30) and tan(30) there are parentheses you must put these functions inside curly brackets {}

documentclass{article}

usepackage{tikz}

usetikzlibrary{angles,quotes}



tikzset{help lines/.style=very thin}

tikzset{My Grid/.style={help lines,color=blue!50}}



begin{document}

begin{tikzpicture}

  draw[My Grid] (-4,-4) grid (4,4);

  draw (-5,0) node[left] {$(-5,0)$} -- (5,0) node[right] {$(5,0)$};

  draw (0,-5) node[below] {$(0,-5)$} -- (0,5) node[above] {$(0,5)$};

  draw (0,0)  circle [radius=3cm];



%   shadedraw[left color=gray, right color=green, draw=green!50!black]

% (0,0) -- (0.75,0)  arc [start angle=0, end angle=30, radius=0.75cm] --  cycle;



  coordinate(O)at(0,0);

  draw[red, very thick] (30:3cm)coordinate(A) 

                         --({3*cos(30)},0)coordinate(B);



  draw [very thick,orange] (3,0) -- (3,{3*tan(30)})coordinate(C);



  pic[fill=green!50!black,

       angle radius=0.75cm,

       angle eccentricity=1.2,

       "(alpha)"] {angle=B--O--A};



   draw (O)--(C);



end{tikzpicture}

end{document} 

share|improve this answer

edited 1 hour ago

answered 4 hours ago

Hafid BoukhouldaHafid Boukhoulda

3,9021622

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Will this ensure that the length is actual value when computed as well or plotted manually with pencil and graph?
  
  – subham soni
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @subhamsoni I notice that the green angle is greeter than 30° I suppose you needed to be 30°
  
  – Hafid Boukhoulda
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have mentioned end angle as 30. Is there anything I am missing
  
  – subham soni
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @subhamsoni Yes you need the specify the correct radius 0.75 cm and not 1cm since the start point is (0.75,0). Also in Tikz there is another manner to draw angles.
  
  – Hafid Boukhoulda
  3 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  it would be great if you can share the other way because precision is always better.
  
  – subham soni
  3 hours ago
  

  
  
  
  

 | 
show 4 more comments

Since in cos(30) and tan(30) there are parentheses you must put these functions inside curly brackets {}

documentclass{article}

usepackage{tikz}

usetikzlibrary{angles,quotes}



tikzset{help lines/.style=very thin}

tikzset{My Grid/.style={help lines,color=blue!50}}



begin{document}

begin{tikzpicture}

  draw[My Grid] (-4,-4) grid (4,4);

  draw (-5,0) node[left] {$(-5,0)$} -- (5,0) node[right] {$(5,0)$};

  draw (0,-5) node[below] {$(0,-5)$} -- (0,5) node[above] {$(0,5)$};

  draw (0,0)  circle [radius=3cm];



%   shadedraw[left color=gray, right color=green, draw=green!50!black]

% (0,0) -- (0.75,0)  arc [start angle=0, end angle=30, radius=0.75cm] --  cycle;



  coordinate(O)at(0,0);

  draw[red, very thick] (30:3cm)coordinate(A) 

                         --({3*cos(30)},0)coordinate(B);



  draw [very thick,orange] (3,0) -- (3,{3*tan(30)})coordinate(C);



  pic[fill=green!50!black,

       angle radius=0.75cm,

       angle eccentricity=1.2,

       "(alpha)"] {angle=B--O--A};



   draw (O)--(C);



end{tikzpicture}

end{document} 

share|improve this answer

edited 1 hour ago

answered 4 hours ago

Hafid BoukhouldaHafid Boukhoulda

3,9021622

documentclass{article}

usepackage{tikz}

usetikzlibrary{angles,quotes}



tikzset{help lines/.style=very thin}

tikzset{My Grid/.style={help lines,color=blue!50}}



begin{document}

begin{tikzpicture}

  draw[My Grid] (-4,-4) grid (4,4);

  draw (-5,0) node[left] {$(-5,0)$} -- (5,0) node[right] {$(5,0)$};

  draw (0,-5) node[below] {$(0,-5)$} -- (0,5) node[above] {$(0,5)$};

  draw (0,0)  circle [radius=3cm];



%   shadedraw[left color=gray, right color=green, draw=green!50!black]

% (0,0) -- (0.75,0)  arc [start angle=0, end angle=30, radius=0.75cm] --  cycle;



  coordinate(O)at(0,0);

  draw[red, very thick] (30:3cm)coordinate(A) 

                         --({3*cos(30)},0)coordinate(B);



  draw [very thick,orange] (3,0) -- (3,{3*tan(30)})coordinate(C);



  pic[fill=green!50!black,

       angle radius=0.75cm,

       angle eccentricity=1.2,

       "(alpha)"] {angle=B--O--A};



   draw (O)--(C);



end{tikzpicture}

end{document} 

share|improve this answer

edited 1 hour ago

answered 4 hours ago

Hafid BoukhouldaHafid Boukhoulda

3,9021622

answered 4 hours ago

Hafid BoukhouldaHafid Boukhoulda

3,9021622

answered 4 hours ago

Hafid BoukhouldaHafid Boukhoulda

3,9021622